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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2295 Radar Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4106    Accepted Submission(s): 1576 Problem Description N cities of the Java Kingdom n…
下面的代码99%参考了这个网站http://www.cnblogs.com/183zyz/archive/2011/08/07/2130193.html 人生的第一道DLX肯定是需要作一些参考的啦. 题意:给你N个城市,M个雷达,你要在其中选K个,问当半径最小是多少的时候可以覆盖到所有的N个城市. 做法:二分所需要的半径r,然后处理出这时雷达能够覆盖到哪些位置.然后就转化成了一个重复覆盖问题,跑一下DLX即可. 花了两天的时间学习了一下DLX这种神奇的数据结构,它在解决精确覆盖问题上尤其有帮助,…
算法详细:Dancing Links博客 1.精确覆盖: ZOJ3209 Treasure Map HUST1017 Exact cover POJ3074 Sudoku 2.可重复覆盖: HDU2295 Radar FZU1686 神龙的难题…
Radar Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2280    Accepted Submission(s): 897 Problem Description N cities of the Java Kingdom need to be covered by radars for being in a state of wa…
GNU Radio Radar Toolbox Install guide Change to any folder in your home directory and enter following commands in your terminal. git clone https://github.com/kit-cel/gr-radar.git // clone this repository cd gr-radar/ mkdir build // make build folder…
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[POJ1328]Radar Installation 试题描述 Assume the coasting is an infinite straight line. Land is in one side of coasting, sea in the other. Each small island is a point locating in the sea side. And any radar installation, locating on the coasting, can onl…
Radar Installation 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=86640#problem/C 题目: Description   Assume the coasting is an infinite straight line. Land is in one side of coasting, sea in the other. Each small island is a point locating…
Radar Installation Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 56826   Accepted: 12814 Description Assume the coasting is an infinite straight line. Land is in one side of coasting, sea in the other. Each small island is a point loca…
题目地址:http://poj.org/problem?id=1328 /* 贪心 (转载)题意:有一条海岸线,在海岸线上方是大海,海中有一些岛屿, 这些岛的位置已知,海岸线上有雷达,雷达的覆盖半径知道, 问最少需要多少个雷达覆盖所有的岛屿. (错误)思路:我开始是想从最左边的点雷达能探测的到的最右的位置出发,判断右边其余的点是否与该点距离小于d 是,岛屿数-1:不是,雷达数+1,继续... (正确)思路:每个岛屿的座标已知,以雷达半径为半径画圆,与x轴有两个交点. 也就是说,若要覆盖该岛,雷达…