传送门 Time Limit: 3000MS Memory Limit: 65536K Description There are N cities in a country, and there is one and only one simple path between each pair of cities. A merchant has chosen some paths and wants to earn as much money as possible in each path.…
POJ 3278 Catch That Cow(赶牛行动) Time Limit: 1000MS Memory Limit: 65536K Description - 题目描述 Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line…
The merchant Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 6864 Accepted: 2375 Description There are N cities in a country, and there is one and only one simple path between each pair of cities. A merchant has chosen some paths and w…
BFS算法与树的层次遍历很像,具有明显的层次性,一般都是使用队列来实现的!!! 常用步骤: 1.设置访问标记int visited[N],要覆盖所有的可能访问数据个数,这里设置成int而不是bool,基于一个考虑,多次循环时不用每次都清空visited,传递进去每次一个数字即可,比如第一次标记为1,判断也采用==1,之后递加即可. 2.设置一个node,用来记录相关参数和当前的步数,比如: struct node { int i; int j; int k; int s;//步数 }; 3.设计…
The merchant Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 4556 Accepted: 1576 Description There are N cities in a country, and there is one and only one simple path between each pair of cities. A merchant has chosen some paths and w…
Description There are N cities in a country, and there is one and only one simple path between each pair of cities. A merchant has chosen some paths and wants to earn as much money as possible in each path. When he move along a path, he can choose on…