Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: TrueExample 2: Input: 5 / \ 3 6 / \ \ 2 4…
给定一个二叉搜索树和一个目标结果,如果 BST 中存在两个元素且它们的和等于给定的目标结果,则返回 true. struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } }; class Solution { public: TreeNode* node; bool findTarget(TreeNo…
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two numbers such that they add up to the target, where index1 mu…
给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数.函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2.请注意,返回的下标值(index1 和 index2)不是从零开始的.你可以假设每个输入都只有一个解决方案,而且你不会重复使用相同的元素.输入:数组 = {2, 7, 11, 15}, 目标数 = 9输出:index1 = 1, index2 = 2详见:https://leetcode.com/problems/two-…
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…
1. 原始题目 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers = [2, 7, 11, 15], target = 9 输出: [1,2] 解释: 2 与 7 之和等于目标数 9 .因此 in…
给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers = [2, 7, 11, 15], target = 9 输出: [1,2] 解释: 2 与 7 之和等于目标数 9 .因此 index1 = 1,…
653. 两数之和 IV - 输入 BST 653. Two Sum IV - Input is a BST 题目描述 给定一个二叉搜索树和一个目标结果,如果 BST 中存在两个元素且它们的和等于给定的目标结果,则返回 true. LeetCode653. Two Sum IV - Input is a BST简单 案例 1: 输入: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 输出: True 案例 2: 输入: 5 / \ 3 6 / \ \ 2 4 7 Target…
1.two sum 用hash来存储数值和对应的位置索引,通过target-当前值来获得需要的值,然后再hash中寻找 错误代码1: Input:[3,2,4]6Output:[0,0]Expected:[1,2] 同一个数字不能重复使用,但这个代码没排除这个问题 class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { vector<int> result; uno…
problem 653. Two Sum IV - Input is a BST 参考 1. Leetcode_easy_653. Two Sum IV - Input is a BST; 完…
Leetcode之二分法专题-167. 两数之和 II - 输入有序数组(Two Sum II - Input array is sorted) 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…
这是悦乐书的第280次更新,第296篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第148题(顺位题号是653).给定二进制搜索树和目标数,如果BST中存在两个元素,使得它们的总和等于给定目标,则返回true.例如: 5 / \ 3 6 / \ \ 2 4 7 目标值:9 输出:true 5 / \ 3 6 / \ \ 2 4 7 目标值:28 输出:false 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Jav…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4098 访问. 给定一个二叉搜索树和一个目标结果,如果 BST 中存在两个元素且它们的和等于给定的目标结果,则返回 true. 输入:  5    / \   3   6  / \   \ 2   4   7 Target = 9 输出: True 输入:  5    / \   3   6  / \   \ 2   4   7 Target = 28 输出: F…
题目要求 Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. 题目分析及思路 给定一个二叉搜索树和一个目标值,若该树中存在两个元素的和等于目标值则返回true.可以先获得树中所有结点的值列表,然后遍历每个值,判断目标值与该值的差是否也在该列表中,并保存每…
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True  Example 2: Input: 5 / \ 3 6 / \ \ 2…
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…
公众号: 爱写bug(ID:icodebugs) 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers = [2, 7, 11, 15], target = 9 输出: [1,2] 解释: 2 与 7…
Design and implement a TwoSum class. It should support the following operations: add and find. add - Add the number to an internal data structure.find - Find if there exists any pair of numbers which sum is equal to the value. For example, add(1); ad…
题目 404. 左叶子之和 如题 题解 类似树的遍历的递归 注意一定要是叶子结点 代码 class Solution { public int sumOfLeftLeaves(TreeNode root) { if(root == null){return 0;} int sum = sumOfLeftLeaves(root.left)+sumOfLeftLeaves(root.right); if(root.left!=null&&root.left.left==null&&am…
[Leetcode] Unique binary search trees 唯一二叉搜索树 Unique Binary Search Trees leetcode java 描述 Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2…
第108题 将一个按照升序排列的有序数组,转换为一棵高度平衡二叉搜索树. 本题中,一个高度平衡二叉树是指一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过 1. 示例: 给定有序数组: [-10,-3,0,5,9], 一个可能的答案是:[0,-3,9,-10,null,5],它可以表示下面这个高度平衡二叉搜索树: 0 / \ -3 9 / / -10 5 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/convert-sorted-a…
Design and implement a TwoSum class. It should support the following operations:add and find. add - Add the number to an internal data structure.find - Find if there exists any pair of numbers which sum is equal to the value. For example,add(1); add(…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:BFS 方法二:DFS 日期 题目地址:https://leetcode.com/problems/two-sum-iv-input-is-a-bst/description/ 题目描述 Given a Binary Search Tree and a target number, return true if there exist two…
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…