小狗在古老的迷宫(maze)中发现了一个骨头,这使它非常着迷.然而,当他把它捡起来的时候,迷宫开始摇晃,狗狗可以感觉到地面下沉(sinking).他意识到这块骨头是一个陷阱(trap),他拼命地想摆脱这个迷宫. 迷宫是的大小为N*M的矩形.迷宫里有一扇门.一开始,门被关闭,它将在第T秒钟打开一段短时间(不到1秒).因此,小狗不得不在第T秒钟到达门口. 在每秒钟,他可以从一个砖移动到上,下,左和右相邻块之一. 一旦他进入一个砖块,这个砖块将开始下沉并在下一秒消失.他不能停留在一砖块超过一秒钟,也不…

Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 90328    Accepted Submission(s): 24554 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…

Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 125945    Accepted Submission(s): 33969 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…

http://acm.hdu.edu.cn/showproblem.php?pid=1010   //题目链接 http://ycool.com/post/ymsvd2s//一个很好理解剪枝思想的博客 http://blog.csdn.net/chyshnu/article/details/6171758//一个很好举例的博客 Problem Description The doggie found a bone in an ancient maze, which fascinated him…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1010 Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 131057    Accepted Submission(s): 35308 Problem Description The doggie fou…

Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 82702    Accepted Submission(s): 22531 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…

Tempter of the Bone Time Limit: 2 Seconds      Memory Limit: 65536 KB The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie could feel the ground sinking. He rea…

Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 58766    Accepted Submission(s): 15983 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…

HDU 1010 题目大意:给定你起点S,和终点D,X为墙不可走,问你是否能在 T 时刻恰好到达终点D. 参考: 奇偶剪枝 奇偶剪枝简单解释: 在一个只能往X.Y方向走的方格上,从起点到终点的最短步数为T1,并记其他任意走法所需步数为T2,则T2-T1一定为偶数. 即若某一点到终点的最短步数为T1,且T3-T1为奇数,则一定无法话费T3步恰好到达终点. /*HDU 1010 ------ Tempter of the Bone DFS*/ #include <cstdio> #include…

Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 70032    Accepted Submission(s): 19286 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…