/* 刚開始想错了,我以为必须是相邻的点才干连接.原来无线距离能够随意连接 对最小生成树理解不够深啊 */ #include<stdio.h> #include<math.h> #include<stdlib.h> #include<string.h> #define N 600 struct node { int u,v; }f[N]; struct nodee{ int u,v; double w; }ff[N*N]; double distance(i…

HDU 1233(最小生成树 模板) #include <iostream> #include <algorithm> #include <cstdio> using namespace std; typedef struct { int a,b; int v; }node; const int maxn=105; int ans; int father[maxn]; node graph[maxn*(maxn-1)/2]; int Find(int x) { if(f…

1.HDU  1102  Constructing Roads    最小生成树 2.总结: 题意:修路,裸题 (1)kruskal //kruskal #include<iostream> #include<cstring> #include<cmath> #include<queue> #include<algorithm> #include<cstdio> #define max(a,b) a>b?a:b using na…

题目链接:http://poj.org/problem?id=2349 思路:由于有S个专门的通道,我们可以先求一次最小生成树,然后对于最小生成树上的边从大到小排序,前S-1条边用S-1个卫星通道连接,那么第S大条边就是我们要找的最小的D了. #include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespa…

poj 1251  && hdu 1301 Sample Input 9 //n 结点数A 2 B 12 I 25B 3 C 10 H 40 I 8C 2 D 18 G 55D 1 E 44E 2 F 60 G 38F 0G 1 H 35H 1 I 353A 2 B 10 C 40B 1 C 200Sample Output 21630 prim算法 # include <iostream> # include <cstdio> # include <cstr…

Qin Shi Huang's National Road System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6137    Accepted Submission(s): 2143 Problem Description During the Warring States Period of ancient China(47…

赤裸裸最小生成树,没啥说的,我用kruskal过的 /* * Author : ben */ #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <ctime> #include <iostream> #include <algorithm> #include <queue> #include <…

思路:直接先求一下最小生成树,然后用树形dp来求最优值.也就是两遍dfs. #include<iostream> #include<algorithm> #include<cstdio> #include<cstring> #include<cmath> #define Maxn 2010 using namespace std; struct Edge{ int u,v; double c; int operator <(const Ed…

Description The Department of National Defence (DND) wishes to connect several northern outposts by a wireless network. Two different communication technologies are to be used in establishing the network: every outpost will have a radio transceiver a…

题意:求最小生成树,和任意两个点之间距离的期望 官方题解: 最后求两遍点的积的时候,还是要判断父子关系. 注意 long long #include <bits/stdc++.h> using namespace std; typedef long long LL; +; int father[maxn]; int Find_Set(int x) { if(x!=father[x]) father[x] = Find_Set(father[x]); return father[x]; } st…