Codeforces1249E By Elevator or Stairs?】的更多相关文章

题意 给定整数c和数组a,b,\(a_i\)表示通过爬楼梯的方法从第\(i\)层到\(i+1\)层需要的时间,\(b_i\)表示通过坐电梯的方法从第\(i\)层到\(i+1\)层需要的时间,坐电梯前需要等c单位时间.即对于\(i<j\),通过爬楼梯的方法要从第\(i\)层到第\(j\)层,需要\(\sum_i^{j-1}a_i\)的时间,而坐电梯需要\(c+\sum_i^{j-1}b_i\)的时间. 解题思路 很明显的dp题,首先考虑最简单的dp思路,对于每次层枚举他是从之前的那一层转移过来的,…
[题目] A. Elevator or Stairs? [描述] Masha要从第x层楼去第y层楼找Egor,可以选择爬楼梯或者坐直升电梯.已知爬楼梯每层需要时间t1:坐直升电梯每层需要时间t2,直升电梯开门或者关门一次需要时间t3,当前直升电梯在第z层楼,直升电梯门是在关闭状态的.如果爬楼梯总时间严格小于坐直升电梯,则选择爬楼梯并输出YES,否则选择坐直升电梯并输出NO. 数据范围:1<=x,y,z,t1,t2,t3<=1000 [思路] 爬楼梯总时长:t1*abs(x-y) 坐直升电梯总时…
Input The first line of the input contains two integers nn and cc (2≤n≤2⋅105,1≤c≤10002≤n≤2⋅105,1≤c≤1000) — the number of floors in the building and the time overhead for the elevator rides. The second line of the input contains n−1n−1 integers a1,a2,…
传送门 首先显然下楼的操作一定是不优的,所以只要考虑上楼 设 $f[i]$ 表示到第 $i$ 层时需要的最少时间 那么首先考虑走楼梯,有转移,$f[i]=f[i-1]+a[i-1]$ 然后考虑坐电梯有:$f[i]=f[j]+(\sum_{k=j}^{i-1}b[k])+c$ 显然那个 $\sum b$ 可以用前缀和搞一下,那么 $f[i]=f[j]+sum[i-1]-sum[j-1]+c$ 我们 $dp$ 转移的时候只要维护一个当前 $f[j]-sum[j-1]$ 的最小值 $mi$ 即可 即…
这题其实和 NIKKEI 2019-2-D Shortest Path on a Line 差不多的啦,都是一种最短路的变形,把多个点和边关联了起来. 题面 你要从一楼到 \(n\) 楼去,每层楼可以选择坐电梯和走楼梯,第 \(i\) 和 \(i+1\) 层之间的楼梯花费 \(a_i\) 时间,而电梯花费 \(b_i\) 时间,而且进出电梯有个时间成本 \(c\). 那么显然,从 \(x\) 楼到 \(y\) 楼走楼梯的花费是 \(\sum\limits_{i=min(x, y)}^{max(x…
A. Elevator or Stairs? 签. #include <bits/stdc++.h> using namespace std; ]; int main() { while (scanf("%d%d%d", &x, &y, &z) != EOF) { ; i < ; ++i) scanf("%d", t + i); ] + * t[]; ]; puts(a <= b ? "YES" :…
A - Yet Another Dividing into Teams 题意:n个不同数,分尽可能少的组,要求组内没有两个人的差恰为1. 题解:奇偶分组. int a[200005]; void test_case() { int n; scanf("%d", &n); for(int i = 1; i <= n; ++i) scanf("%d", &a[i]); sort(a + 1, a + 1 + n); int ans = 1; for…
http://codeforces.com/problemset/problem/1249/E E. By Elevator or Stairs? time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are planning to buy an apartment in a n -floor building. The f…
题目传送门 A .Yet Another Dividing into Teams sol:原先是用比较复杂的方法来解的,后来学弟看了一眼,发现不是1就是2,当出现两个人水平相差为1就分成两组,1组全是奇数,1组全是偶数,必然符合题意. 思维 #include "bits/stdc++.h" using namespace std; #define debug puts("what the fuck"); typedef long long LL; typedef p…
目录 Abstract Introduction Topic Request Elevator Analysis Reading Requests Coordinating Scheduling and controling Elevator simulation Course P5-P6 Reading (and coordinating) Scheduling and controling Elevator simulation P7 Reading and coordinating Sch…
Time Limit: 1sec    Memory Limit:32MB  Description John is moving to the penthouse of a tall sky-scraper. He packed all his stuff in boxes and drove them to the entrance of the building on the ground floor. Unfortunately the elevator is out of order,…
Elevator Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 56481    Accepted Submission(s): 30942 Problem Description The highest building in our city has only one elevator. A request list is made…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 这个爬梯子问题最开始看的时候没搞懂是让干啥的,后来看了别人的分析后,才知道实际上跟斐波那契数列非常相似,假设梯子有n层,那么如何爬到第n层呢,因为每次只能怕1或2步,那…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Have you met this question in a real interview? Yes Example Given an example n=3 , 1…
July 28, 2015 Problem statement: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? The problem is most popular question in the algorit…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Example Given an example n=3 , 1+1+1=2+1=1+2=3 return 3 For the problem, try to thin…
Description The cows are going to space! They plan to achieve orbit by building a sort of space elevator: a giant tower of blocks. They have K (1 <= K <= 400) different types of blocks with which to build the tower. Each block of type i has height h…
From: https://discuss.leetcode.com/topic/89/write-elevator-program-using-event-driven-programming/9 We can divide into three main components: User User presses the floor button (can be up or down direction) to summon the elevator. User presses the el…
[题目链接] The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and…
Search a 2D Matrix Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer…
作业提交时间:10月9日上课前. Design and implement an Elevator Scheduler to aim for both correctness and performance, in managed code. Skills to learn and practice: a)       Peer to peer collaboration b)       Requirement Analysis c)       Design by contract, Int…
Climbing Stairs https://leetcode.com/problems/climbing-stairs/ You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 算法描述 (1)这道题其实是一道fibon…
Space Elevator Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9970   Accepted: 4738 Description The cows are going to space! They plan to achieve orbit by building a sort of space elevator: a giant tower of blocks. They have K (1 <= K <…
Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will s…
[前言] 很久没有纯粹的写写小代码,偶然想起要回炉再来,就去HDU随便选了个最基础的题,也不记得曾经AC过:最后吃惊的发现,思路完全不一样了,代码风格啥的也有不小的变化.希望是成长了一点点吧.后面定期去做做题.保持青春的活力! 1.青年回炉 Problem : 1008 ( Elevator )   Run ID Submit Time Judge Status Pro.ID Exe.Time Exe.Memory Code Len. Language Author 9098607 2013-0…
Elevator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 51396 Accepted Submission(s): 28377 Problem Description The highest building in our city has only one elevator. A request list is made up w…
The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seco…
原题 Climbing Stairs 求斐波那契数列的第N项,开始想用通项公式求解,其实一个O(n)就搞定了. class Solution { public: int climbStairs(int n) { ) ; ; ; ; i<n; ++i) { int t = n2; n2 = n1 + n2; n1 = t; } return n2; } }; 还是觉得没有ACM难度,继续做吧.…
1- 问题描述 You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 2- 思路分析 很自然的会想到递归,假设 n 级台阶有 T(n) 种不同走法.最后一步存在两种情况:剩下 1 级台阶,或者,剩下 2 级台阶. 第一种情…
软件工程 --- Pair Project: Elevator Scheduler [电梯调度算法的实现和测试] [附加题] 首先,在分组之前,我和室友薛亚杰已经详细阅读了往届学长的博客,认为电梯调度这个项目应该先做UI会比较好一点,于是动手展开了UI的编写.但分组结果并没有如我们所愿,但我们依然共同进行了UI的编写,最后在两个小组成员的共同努力下,大致实现了UI.希望在第二次结对编程中能够再一起对UI界面进行更新和完善. UI编写人员 周敏轩 192 薛亚杰 193 另外,特别感谢毛宇大神对我…