It's All In The Mind 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5742 Description Professor Zhang has a number sequence a1,a2,...,an. However, the sequence is not complete and some elements are missing. Fortunately, Professor Zhang remembers some…

It's All In The Mind 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5742 Description Professor Zhang has a number sequence a1,a2,...,an. However, the sequence is not complete and some elements are missing. Fortunately, Professor Zhang remembers some…

Chess Problem Description   Alice and Bob are playing a special chess game on an n × 20 chessboard. There are several chesses on the chessboard. They can move one chess in one turn. If there are no other chesses on the right adjacent block of the mov…

题目:传送门. 题意:求题目中的公式的最大值,且满足题目中的三个条件. 题解:前两个数越大越好. #include <iostream> #include <algorithm> #include <cstdio> #include <cstring> using namespace std; int gcd(int a,int b) { if(!b) return a; return gcd(b,a%b); } int main() { int t; ci…

It's All In The Mind Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 409    Accepted Submission(s): 189 Problem Description Professor Zhang has a number sequence a1,a2,...,an. However, the seque…

It's All In The Mind Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 505    Accepted Submission(s): 225 Problem Description Professor Zhang has a number sequence a1,a2,...,an . However, the sequ…

链接:HDU - 6409:没有兄弟的舞会 题意: 题解: 求出最大的 l[i] 的最大值 L 和 r[i] 的最大值 R,那么 h 一定在 [L, R] 中.枚举每一个最大值,那么每一个区间的对于答案的贡献就是一个等差数列的和(乘法分配律),将每一个和乘起来就是该最大值的对于答案的贡献.但是相同最大值可能来自于多个区间,如果枚举每一个可能出现最大值的区间,那么会超时,所以需要一个神奇的方法,我也不知道原理是什么,但是数学上就是直接的式子,可以分解出来. #include <bits/stdc+…

小C的倍数问题 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 481    Accepted Submission(s): 278 Problem Description 根据小学数学的知识,我们知道一个正整数x是3的倍数的条件是x每一位加起来的和是3的倍数.反之,如果一个数每一位加起来是3的倍数,则这个数肯定是3的倍数. 现在给定进制…

主题链接:http://acm.hdu.edu.cn/showproblem.php?pid=3153 Problem Description Before "automaton" was a theoretic computer science concept, it meant "mechanical figure or contrivance constructed to act as if by its own motive power; robot." E…

题意: 给出一个n*m的地图,要求从左上角(0, 0)走到右下角(n-1, m-1). 地图中每个格子中有一个值.然后根据这些值求出一个最小值. 这个最小值要这么求—— 这是我们从起点走到终点的路径,其中N是地图的长,M是地图的宽,Ai表示路径中第i个点的值,Aavg表示路径中所有的点的值的平均值.要求这个式子的值最小. 我们可以将它转化为 好了,推到这里,我们需要的数学知识就结束了(实际上以我的数学知识也只能做到这里了……).然后dp就好了—— Dp[i][j][k],i表示第i行,j表示第j…