整体上3个题都是求subarray,都是同一个思想,通过累加,然后判断和目标k值之间的关系,然后查看之前子数组的累加和. map的存储:560题是存储的当前的累加和与个数 561题是存储的当前累加和的余数与第一次出现这个余数的位置 325题存储的是当前累加和与第一次出现这个和的位置 其实561与325都是求的最长长度,那就一定要存储的是第一次出现满足要求的位置,中间可能还出现这种满足要求的情况,但都不能进行存储 560. Subarray Sum Equals K 求和为k的连续子数组的个数 h…

Given a list of non-negative numbers and a target integer k, write a function to check if the array has a continuous subarray of size at least 2 that sums up to the multiple of k, that is, sums up to n*k where n is also an integer. Example 1: Input:…

［抄题］: Given a list of non-negative numbers and a target integer k, write a function to check if the array has a continuous subarray of size at least 2 that sums up to the multiple of k, that is, sums up to n*k where n is also an integer. Example 1: I…

class Solution { public: bool checkSubarraySum(vector<int>& nums, int k) { unordered_map<int,int> allsum; allsum.insert(make_pair(,-)); ; ;i<nums.size();++i) { sum+=nums[i]; if(k)sum%=k; auto j=allsum.find(sum); if(j!=allsum.end()) { )r…

非负数组中找到和为K的倍数的连续子数组 详见:https://leetcode.com/problems/continuous-subarray-sum/description/ Java实现: 方法一: class Solution { public boolean checkSubarraySum(int[] nums, int k) { for(int i=0;i<nums.length;++i){ int sum=nums[i]; for(int j=i+1;j<nums.length…

题目如下: 解题思路:本题需要用到这么一个数学定理.对于任意三个整数a,b,k(k !=0),如果 a%k = b%k,那么(a-b)%k = 0.利用这个定理,我们可以对数组从头开始进行求和,同时利用字典保存余数(key:余数,value:最早出现这个余数的元素下标),每累加一个元素都对k取余数,如果余数在字典中存在并且两个元素之间的下标差大于等于2,即表示存在这样的subarray.而对于k=0的情况,必须要出现至少两个出现至少连续两个0才能符合条件:当然,因为0*k = 0,所以如果数组中…

Given an integer array, find a continuous rotate subarray where the sum of numbers is the biggest. Your code should return the index of the first number and the index of the last number. (If their are duplicate answer, return anyone. The answer can b…

LintCode 402: Continuous Subarray Sum 题目描述 给定一个整数数组,请找出一个连续子数组,使得该子数组的和最大.输出答案时,请分别返回第一个数字和最后一个数字的下标.(如果两个相同的答案,请返回其中任意一个) 样例 给定[-3, 1, 3, -3, 4], 返回[1,4]. Thu Feb 23 2017 思路 本题有很多解法,最巧妙的解法就是一遍扫描记忆的方法了,时间复杂度为\(O(n)\). 用一个变量记录连续累加的和,当和为负数时,变量清零,从下一个数字…

Continuous Subarray Sum II   Given an circular integer array (the next element of the last element is the first element), find a continuous subarray in it, where the sum of numbers is the biggest. Your code should return the index of the first number…

Given an integer array, find a continuous subarray where the sum of numbers is the biggest. Your code should return the index of the first number and the index of the last number. (If their are duplicate answer, return anyone) Have you met this quest…