arc 092C 2D Plane 2N Points

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arc 092C 2D Plane 2N Points

题意: 有n个红色的点和n个蓝色的点,如果红色的点的横坐标和纵坐标分别比蓝色的点的横坐标和纵坐标小,那么这两个点就可以成为一对友好的点. 问最多可以形成多少对友好的点. 思路: 裸的二分图匹配,对于满足条件的两个点连边. wa了两发,板子错了,还是得用果苣的!. 代码: #include <stdio.h> #include <string.h> ; int link[N]; bool mp[N][N]; bool vis[N]; struct node { int x,y; }…

【AtCoder Regular Contest 092】C.2D Plane 2N Points【匈牙利算法】

C.2D Plane 2N Points 题意:给定N个红点二维坐标N个蓝点二维坐标,如果红点横纵坐标都比蓝点小,那么它们能够构成一组.问最多能构成多少组. 题解:把满足要求的红蓝点连线,然后就是匈牙利算法(详情见这里,写的好棒!) #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; ; int a[maxn],b[max…

AtCoder Regular Contest 092 C - 2D Plane 2N Points(二分图匹配)

Problem Statement On a two-dimensional plane, there are N red points and N blue points. The coordinates of the i-th red point are (ai,bi), and the coordinates of the i-th blue point are (ci,di). A red point and a blue point can form a friendly pair w…

AtCoder Regular Contest 092 2D Plane 2N Points AtCoder - 3942 （匈牙利算法）

Problem Statement On a two-dimensional plane, there are N red points and N blue points. The coordinates of the i-th red point are (ai,bi), and the coordinates of the i-th blue point are (ci,di). A red point and a blue point can form a friendly pair w…

AtCoderBeginner091-C 2D Plane 2N Points 模拟问题

题目链接:https://abc091.contest.atcoder.jp/tasks/arc092_a 题意 On a two-dimensional plane, there are N red points and N blue points. The coordinates of the i-th red point are (ai,bi), and the coordinates of the i-th blue point are (ci,di). A red point and…

Microsoft - Find the K closest points to the origin in a 2D plane

Find the K closest points to the origin in a 2D plane, given an array containing N points. 用 max heap 做 /* public class Point { public int x; public int y; public Point(int x, int y) { this.x = x; this.y = y; } } */ public List<Point> findKClosest(P…

[LeetCode OJ] Max Points on a Line—Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.

//定义二维平面上的点struct Point { int x; int y; Point(, ):x(a),y(b){} }; bool operator==(const Point& left, const Point& right) { return (left.x==right.x && left.y==right.y); } //求两个点连接成的直线所对应的斜率 double line_equation(const Point& P1, const Poi…