1047. Student List for Course (25) Zhejiang University has 40000 students and provides 2500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification: Each…

1047 Student List for Course (25 分) Zhejiang University has 40,000 students and provides 2,500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification: E…

1047 Student List for Course (25 分)   Zhejiang University has 40,000 students and provides 2,500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification:…

1047 Student List for Course Zhejiang University has 40,000 students and provides 2,500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification: Each inp…

Zhejiang University has 40000 students and provides 2500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification: Each input file contains one test case.…

https://pintia.cn/problem-sets/994805342720868352/problems/994805433955368960 Zhejiang University has 40,000 students and provides 2,500 courses. Now given the registered course list of each student, you are supposed to output the student name lists…

Zhejiang University has 40000 students and provides 2500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification: Each input file contains one test case.…

1039 Course List for Student 依靠unordered_map<string,set<int>> ans 解决问题. 这次依靠unordered_map<int ,vector<string>> ans;如果vector改成set(自带自排序+去重)最后一个测试点会超时导致无法通过. 所以每次输出结果之前,都要对vector重新排序一次. STL:unordered_map,vector,sort,string. #include&…

Zhejiang University has 40,000 students and provides 2,500 courses. Now given the registered course list of each student, you are supposed to output the student name lists of all the courses. Input Specification: Each input file contains one test cas…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<vector> using namespace std; +; struct X { ]; vect…

一开始是建立了course[2501][40001]数组,存储每节课的学生编号然后for循环两层输出,但这样复杂度为O(2500*40000),也很明显导致最后时间超时后来发现最多40000学生,每个学生最多选20门课,那么总共也就40000*20所以直接就存储学生-课程的信息,然后排个序,按照课程从小到大,课程一样的话则按字典序然后从头扫一遍即可,复杂度O(80000)不过要注意一点,有些课可能并没有出现,所以要做个判断,输出x 0. #include <iostream> #include…

题意: 输入两个正整数N和K(N<=40000,K<=2500),接下来输入N行,每行包括一个学生的名字和所选课程的门数,接着输入每门所选课程的序号.输出每门课程有多少学生选择并按字典序输出学生的名字. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; vector<]; int main(){ ios::sync_with_stdio…

1047. Student List for Course (25) 时间限制 400 ms 内存限制 64000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Zhejiang University has 40000 students and provides 2500 courses. Now given the registered course list of each student, you are supposed to output…

1047. Student List for Course (25) 时间限制 400 ms 内存限制 64000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Zhejiang University has 40000 students and provides 2500 courses. Now given the registered course list of each student, you are supposed to output…

准备每天刷两题PAT真题.(一句话题解) 1001 A+B Format  模拟输出,注意格式 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; string ans = ""; int main() { ; cin >> a >> b; c = a + b; ) {…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

浏览全部代码:请戳 本文谨代表个人思路,欢迎讨论;) 1041. Be Unique (20) 题意 给出 N (<=105)个数(数值范围为 [1, 104]),找到其中不重复的第一个数字.比如给出5 31 5 88 67 88 17 , 答案是 31 . 分析 简单模拟题,开一个大数组int a[10001];,以读入的数为下标,记录 count:a[index] ++;.结果输出第一个存储为 1 的下标:if (a[index] == 1). 1042. Shuffling Machine…

最短路径 Emergency (25)-PAT甲级真题(Dijkstra算法) Public Bike Management (30)-PAT甲级真题(Dijkstra + DFS) Travel Plan (30)-PAT甲级真题(Dijkstra + DFS,输出路径,边权) All Roads Lead to Rome (30)-PAT甲级真题-Dijkstra + DFS Online Map (30)-PAT甲级真题(Dijkstra + DFS) 最短路径扩展问题 要求数最短路径有多…

1051 Pop Sequence (25分) [stack] 简答的栈模拟题,只要把过程想清楚就能做出来. 扫描到某个元素时候,假如比栈顶元素还大,说明包括其本身的在内的数字都应该入栈.将栈顶元素和序列比对即可,相同则弹栈,继续扫描:否则无法生成满足条件的序列.注意栈满时不能入栈 #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int maxn =…

考虑到PAT甲级考试和开学后的XCPC比赛,决定寒假把PAT (Advanced Level) Practice刷完,进度条会在这篇博客下更新.由于主要以记录为主,大体上不会像单篇题解那么详细,但是对问题的思考,代码的简洁性.可读性还是有保障的,欢迎看到的小伙伴和我讨论 2021.1.10 1001 A+B Format (20分) 很久没写题了,没想到卡了半个小时,惭愧.这里是要把结果用逗号分隔成三组,即以千为单位,不足的话则不必要填逗号,我最多只添了一个逗号,要看清题目意思再动笔 #incl…

vector 常用函数实例 (1)push_back() (2)pop_back() (3)size() (4)clear():清空vector中所有元素 (5)insert():insert(it, x)向vector的任意迭代器it处插入一个元素x,insert(vi.begin()+2,-1); (6)erase():erase(vi.begin()+3)删除第四个元素:erase(first,last)删除[first,last)内所有元素: A1039.Course List for…

java.io.NotSerializableException: test.io.file.Student    at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1183)    at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:347)    at test.io.file.Demo4.test2(Demo4.java:36)…

题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=1047 题意:见中文题面 思路:该题是求二维的子矩阵的最大值与最小值的差值尽量小.所以可以考虑求出每个子矩阵的最大值和最小值.考虑一维求子段的最小值/最大值的思路.滑动窗口+单调队列. 转换成二维.设minNum[i][j]表示右下角为(i,j)的子矩阵的最小值.先对矩阵每一行用一维的做法求出每一行的子段的最小值,然后同样的方法求列的最值.注意在求列的子段最小值时比较的元素不是原矩阵的元素…

定义Student类 package org; public class Student { private String _name = null; ; ; public Student() { } public Student(String name, int age, int score) { _name = name; _age = age; _score = score; } public void setName(String name) { _name = name; } publ…

一.            设有一数据库,包括四个表:学生表(Student).课程表(Course).成绩表(Score)以及教师信息表(Teacher).四个表的结构分别如表1-1的表(一)~表(四)所示,数据如表1-2的表(一)~表(四)所示.用SQL语句创建四个表并完成相关题目. 表1-1数据库的表结构 表(一)Student (学生表) 字段名 数据类型 可否为空 含 义 Sno Varchar2(3) 否 学号(主键) Sname Varchar2(8) 否 学生姓名 Ssex Va…

1047: 小A的计算器 时间限制: 1 Sec  内存限制: 128 MB提交: 124  解决: 105[提交][状态][讨论版] 题目描述 以往的操作系统内部的数据表示都是二进制方式,小A新写了一个操作系统,系统内部的数据表示为26进制,其中0-25分别由a-z表示.现在小A要在这个操作系统上实现一个计算器,这个计算器要能实现26进制数的加法运算.你能帮小A实现这个计算器吗? 输入 输入的第一行包括一个整数N(1<=N<=100).接下来的N行每行包括两个26进制数x和y,它们之间用空格…

项目:蒙文词语检索 日期:2016-05-01 提示:The constructor User.Student(String, String, String) is not visible 出处:Dbdao.insert(new Student("Achilles", "Male", "14")); 解决方法: 原代码:Student(String Name, String Sex, String Age) 修改成:public Student(…

第三题 有如下Student 对象, private String name; private int age; private int score; private String classNum; 其中,classNum 表示学生的班号,例如“class05”. 有如下List List list = new ArrayList(); list.add(new Student(“Tom”, 18, 100, “class05”)); list.add(new Student(“Jerry”,…

create trigger Delete_sc on student for delete as delete student_course where student_course.s_no in(select s_no from deleted)…