题目链接:https://vjudge.net/contest/218427#problem/C 题目大意: 老板要给很多员工发奖金, 但是部分员工有个虚伪心态, 认为自己的奖金必须比某些人高才心理平衡: 但是老板很人道, 想满足所有人的要求, 并且很吝啬,想画的钱最少 输入若干个关系 a b a c c b 意味着a 的工资必须比b的工资高 同时a 的工资比c高: c的工资比b高 当出现环的时候输出-1 #include<iostream> #include<cstring> #…

HDU.2647 Reward(拓扑排序 TopSort) 题意分析 裸的拓扑排序 详解请移步 算法学习 拓扑排序(TopSort) 这道题有一点变化是要求计算最后的金钱数.最少金钱值是888,最少的差额是1,如1号的人比2号钱要多,2号至少是1号人的钱数+1.根据拓扑排序的思想,我们只需要类比二叉树的层序遍历,每次取出入度为0的节点做处理,累加金钱数量,然后再取出入度为0的节点处理.直到取出所有的点或者判断成环即可. 代码总览 #include <iostream> #include <…

hdu 2647 Reward Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2647 题意是给你n点m条有向边,叶子点(出度为0)上的值为888,父亲点为888+1,依次计算... 让你求最小的值,但是中间出现有向环就不行了,输出-1. 拓扑排序队列实现,因为叶子是最小的,所以把边反向就可以求了. //拓扑队列实现 //就是先把入度为0的先入队,然后每次出队的时候把相邻的点的入度减1,要是入度为0则再入队,不断循环直到队列为空 //时间复杂度为O(N + E) //这题就是把边…

Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewards. The workers will compare their rewards ,and some one may…

Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewards. The workers will compare their rewards ,and some…

Problem Description Dandelion's uncle is a boss of a factory. As the spring festival is coming , he wants to distribute rewards to his workers. Now he has a trouble about how to distribute the rewards.The workers will compare their rewards ,and some…

令每一个员工都有一个自己的等级level[i] , 员工等级越高,那么工资越高,为了使发的钱尽可能少,所以每一级只增加一单位的钱 输入a b表示a等级高于b,那么我们反向添加边,令b—>a那么in[a]++,再进行拓扑排序,每次都让边的终点的level值大于起始点,那么要用max取较大值 #include <iostream> #include <cstdio> #include <cstring> #include <queue> using nam…

此题的关键在于分层次,最低一层的人的奖金是888,第二层是888+1 …… 分层可以这样实现.建立反向图.在拓扑排序的时候,第一批入度为0的点就处于第一层,第二批处于第二层 …… 由于是逐个遍历入度为0的点,所以怎么实现上面所说的第一批,第二批就需要动点脑. 可以试试下面的测试数据: 4 31 32 34 3 4 31 22 34 3 4 21 23 4 6 31 23 45 6 测试结果依次是: 3555 3556 3554  5331 #include<iostream> #include…

/* ASCII码排序 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 160482    Accepted Submission(s): 64810     Problem Description 输入三个字符后,按各字符的ASCII码从小到大的顺序输出这三个字符.     Input 输入数据有多组,每组占一行,有三个字符组成,之间…