题目链接:传送门 题目大意:给你一幅图(单向边),找出从起点到终点有多少条不同路径(最短路或者比最短路长度大1) 题目思路:二维dijkstra,真的是要对dijkstra理解非常透彻才行,距离数组d开成二维表示最短路与次短路,同时需要一个cnt数组,记录有多少条路径 对于当前点有四种更新情况: 1.if(距离<最短路) 更新最短路与次短路(包括路径数) 2.if(距离==最短路) 更新最短路路径数 3.if(距离<次小) 更新次短路(包括路径数) 4.if(距离==距离) 更新次短路路径数…

Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9276   Accepted: 3924 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beauti…

Sightseeing Cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8331   Accepted: 2791 Description Farmer John has decided to reward his cows for their hard work by taking them on a tour of the big city! The cows must decide how best to…

Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8859   Accepted: 3728 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beauti…

Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6986   Accepted: 2901 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beauti…

Sightseeing tour   Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beautiful city. They want to construct the tour so that every street in the city is vis…

Sightseeing Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1023    Accepted Submission(s): 444 Problem Description Tour operator Your Personal Holiday organises guided bus trips across the Ben…

Sightseeing tour Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 8276 Accepted: 3489 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beautiful…

题目链接:Sightseeing 题意:求最短路和比最短路长度+1的所有路径条数. 附代码:用数组记录最短和次短路径的长度和条数,一次更新,直到没有边可以更新. #include <stdio.h> #include <string.h> #include <iostream> #include <vector> using namespace std; #define maxn 1010 struct Node { int to, val; Node(in…

Sightseeing Trip Time limit: 0.5 secondMemory limit: 64 MB There is a travel agency in Adelton town on Zanzibar island. It has decided to offer its clients, besides many other attractions, sightseeing the town. To earn as much as possible from this a…

                                                            Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9100   Accepted: 3830 Description The city executive board in Lund wants to construct a sightseeing tour by bus…

http://poj.org/problem?id=3463 Sightseeing Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6420   Accepted: 2270 Description Tour operator Your Personal Holiday organises guided bus trips across the Benelux. Every day the bus moves from…

DescriptionThere is a travel agency in Adelton town on Zanzibar island. It has decided to offer its clients, besides many other attractions, sightseeing the town. To earn as much as possible from this attraction, the agency has accepted a shrewd deci…

Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 8628   Accepted: 3636 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beauti…

Sightseeing Cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8915   Accepted: 3000 Description Farmer John has decided to reward his cows for their hard work by taking them on a tour of the big city! The cows must decide how best to…

POJ 1637 Sightseeing tour 题目链接 题意:给一些有向边一些无向边,问能否把无向边定向之后确定一个欧拉回路 思路:这题的模型很的巧妙,转一个http://blog.csdn.net/pi9nc/article/details/12223693 先把有向边随意定向了,然后依据每一个点的入度出度之差,能够确定每一个点须要调整的次数,然后中间就是须要调整的边,容量为1,这样去建图最后推断从源点出发的边是否都满流就可以 代码: #include <cstdio> #includ…

这是现场完整做出来的唯一一道题Orz..而且还调了很久的bug.还是太弱了. Problem When you travel, you like to spend time sightseeing in as many cities as possible, but sometimes you might not be able to because you need to catch the bus to the next city. To maximize your travel enjoy…

Given an array A of positive integers, A[i] represents the value of the i-th sightseeing spot, and two sightseeing spots i and j have distance j - i between them. The score of a pair (i < j) of sightseeing spots is (A[i] + A[j] + i - j) : the sum of…

Sightseeing Time Limit: 2000MS   Memory Limit: 65536K Total Submissions:10005   Accepted: 3523 Description Tour operator Your Personal Holiday organises guided bus trips across the Benelux. Every day the bus moves from one city S to another city F. O…

描述 The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beautiful city. They want to construct the tour so that every street in the city is visited exactly once. The bus s…

Sightseeing trip Time Limit: 1000MS   Memory Limit: 65536K Total Submissions:8588   Accepted:3224   Special Judge Description There is a travel agency in Adelton town on Zanzibar island. It has decided to offer its clients, besides many other attract…

Given an array A of positive integers, A[i] represents the value of the i-th sightseeing spot, and two sightseeing spots i and j have distance j - i between them. The score of a pair (i < j) of sightseeing spots is (A[i] + A[j] + i - j) : the sum of…

原题链接 鸣谢:AGC 018E.Sightseeing Plan(组合 DP) 本蒟蒻认为,本题堪称网格路径问题观止. 因为涵盖了不少网格路径问题的处理方法和思路. 一句话题意: 给你三个矩形. 三个矩形从左下到右上排开.矩形顶点坐标范围是1e6 1≤X1≤X2<X3≤X4<X5≤X6≤106 1≤Y1≤Y2<Y3≤Y4<Y5≤Y6≤106 大概就是这样: 对于所有的1中选择一个点P1,2中选择一个点P2,3中选择一个点P3. 求从P1到P2再到P3的最短路径条数之和. 从一个矩…

P2868 [USACO07DEC]观光奶牛Sightseeing Cows [](https://www.cnblogs.com/images/cnblogs_com/Tony-Double-Sky/1270353/o_YH[_INPMKE_4RY]3DF(33@G.png) 错误日志: dfs 判负环没有把初值赋为 \(0\) 而是 \(INF\), 速度变慢 Solution 设现在走到了一个环, 环内有 \(n\) 个点, \(n\) 条边, 点权为 \(f_{i}\), 边权为 \(e…

Sightseeing tour Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6448   Accepted: 2654 Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that tourists can see every corner of the beauti…

hdu3191题意:求出次短路的长度和条数 #include<iostream> #include<cstdio> #include<cstring> #include<queue> #include<vector> using namespace std; const int MAXN=55; const int inf=1<<30; struct Edge{ int v,w; }; vector<Edge>vet[MA…

嗯,这是我上一篇文章说的那本宝典的第二题,我只想说,真TM是本宝典……做的我又痛苦又激动……(我感觉ACM的日常尽在这张表情中了) 题目链接:http://poj.org/problem?id=1637 Time Limit: 1000MS Memory Limit: 10000K Description The city executive board in Lund wants to construct a sightseeing tour by bus in Lund, so that t…

[POJ3621]Sightseeing Cows 题意:在给定的一个图上寻找一个环路,使得总欢乐值(经过的点权值之和)/ 总时间(经过的边权值之和)最大. 题解:显然是分数规划,二分答案ans,将每条边的权值变成(ans*边权-2*起始点点权),然后我们希望找出一个环,使得环上的总边权<0 (一开始我把题意理解错了,题中给的是单向边,我把它当成是双向边+每条边只能走一次了~,想出一堆做法都接连pass掉) 然后就直接用SPFA判负环就好了嘛!由于原图不一定联通,所以一开始就把所有点都入队就完事…

Sightseeing Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 639    Accepted Submission(s): 249 Problem Description Tour operator Your Personal Holiday organises guided bus trips across the Benel…

[POJ3621][洛谷2868]Sightseeing Cows(分数规划) 题面 Vjudge 洛谷 大意: 在有向图图中选出一个环,使得这个环的点权\(/\)边权最大 题解 分数规划 二分答案之后把每条边的边权换为\(mid·\)边权-出点的点权 然后检查有没有负环就行啦 #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<cmath&g…