Jin Ge Jin Qu hao (If you smiled when you see the title, this problem is for you ^_^) For those who don’t know KTV, see: http://en.wikipedia.org/wiki/Karaoke_box There is one very popular song called Jin Ge Jin Qu(). It is a mix of 37 songs, and is e…
• Don’t sing a song more than once (including Jin Ge Jin Qu). • For each song of length t, either sing it for exactly t seconds, or don’t sing it at all. • When a song is finished, always immediately start a new song. 每首歌唱一次,在一定时间类,要求唱歌数量尽量多,时间尽量长.而且…
InputThe first line contains the number of test cases T (T ≤ 100). Each test case begins with two positiveintegers n, t (1 ≤ n ≤ 50, 1 ≤ t ≤ 109), the number of candidate songs (BESIDES Jin Ge Jin Qu)and the time left (in seconds). The next line cont…
(If you smiled when you see the title, this problem is for you ^_^) For those who don’t know KTV, see: http://en.wikipedia.org/wiki/Karaoke_box There is one very popular song called Jin Ge Jin Qu(). It is a mix of 37 songs, and is extremely long (11…
分析可知,虽然t<109,但是总曲目时间大于t,实际上t不会超过180*n+678.此问题涉及到两个目标信息,首先要求曲目数量最多,在此基础上要求所唱的时间尽量长.可以定义 状态dp[i][j]表示前i首歌曲,恰好唱的时间为j时,所唱的最长时间,于是就是裸的01背包了. /*----UVa12563 Jin Ge Jin Qu */ #define _CRT_SECURE_NO_DEPRECATE #include<iostream> #include<vector> #in…
