Find a way Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 25379    Accepted Submission(s): 8243 Problem Description Pass a year learning in Hangzhou, yifenfei arrival hometown Ningbo at finally…

HDU 2612 Find a way(找条路) 00 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)   Problem Description - 题目描述 Pass a year learning in Hangzhou, yifenfei arrival hometown Ningbo at finally. Leave Ningbo one year, yifenfei have many people to…

HDU.2612 Find a way (BFS) 题意分析 圣诞节要到了,坤神和瑞瑞这对基佬想一起去召唤师大峡谷开开车.百度地图一下,发现周围的召唤师大峡谷还不少,这对基佬纠结着,该去哪一个...坤神:我要去左边的这个(因为离自己比较近 哈哈~)..瑞瑞:我要去右边的这个(因为离自己比较近 嘿嘿~) --..这对基佬闹矛盾了,开车有危险了! 为了不让他们去召唤师大峡谷坑人,riot决定让他们去X召唤师大峡谷,保证他俩所走的路程和最短.每走一个点需要花费11分钟,输出他们一共花费多少时间(最短时…

题目传送门 /* BFS:和UVA_11624差不多,本题就是分别求两个点到KFC的最短路,然后相加求最小值 */ /************************************************ Author :Running_Time Created Time :2015-8-4 19:36:36 File Name :HDOJ_2612.cpp ************************************************/ #include <cstd…

题目代号:HDU 2612 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2612 Find a way Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 15919    Accepted Submission(s): 5110 Problem Description Pass a year…

Problem Description Pass a year learning in Hangzhou, yifenfei arrival hometown Ningbo at finally. Leave Ningbo one year, yifenfei have many people to meet. Especially a good friend Merceki.Yifenfei’s home is at the countryside, but Merceki’s home is…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2612 Problem DescriptionPass a year learning in Hangzhou, yifenfei arrival hometown Ningbo at finally. Leave Ningbo one year, yifenfei have many people to meet. Especially a good friend Merceki.Yifenfei’…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2612 Find a way Description Pass a year learning in Hangzhou, yifenfei arrival hometown Ningbo at finally. Leave Ningbo one year, yifenfei have many people to meet. Especially a good friend Merceki.Yifen…

http://acm.hdu.edu.cn/showproblem.php?pid=2612 bfs两次就可将两个人到达所有kfc的时间求出,取两人时间之和最短的即可,这个有点不符合实情,题目应该出两人最大时间最小才对 #include <cstdio> #include <cstring> #include <queue> using namespace std; const int inf=0x3fffffff; char maz[300][301]; int n,…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=2612 Find a way Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6718    Accepted Submission(s): 2236 Problem Description Pass a year learning in Han…