【leetcode】347. Top K Frequent Elements】的更多相关文章

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 解题方法 字典 优先级队列 日期 题目地址:https://leetcode.com/problems/top-k-frequent-elements/description/ 题目描述 Given a non-empty array of integers, return the k most frequent elements. For example,…
题目地址:https://leetcode.com/problems/top-k-frequent-elements/ 从一个数组中求解出现次数最多的k个元素,本质是top k问题,用堆排序解决. 关于堆排序,其时间复杂度在最好和最坏的场景下都是O(nlogn). 一开始想定义一个结构体,包含元素和元素个数两个成员,后直接用pair存储即可. 解题思路: 1. 分别统计每个数字的个数,建立数字和个数的映射,用pair存储,first=数字个数,second=数字,然后存入集合. 2. 以不同数字…
[LeetCode]692. Top K Frequent Words 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/top-k-frequent-words/description/ 题目描述: Given a non-empty list of words, return the k most frequent elements. Your answer should be sorted by frequency f…
版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - Leetcode 347. Top K Frequent Elements - 题解 在线提交: https://leetcode.com/problems/top-k-frequent-elements/ Description Given a non-empty array of integers…
Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…
Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: 347. Top K Frequent ElementsYou may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's…
Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…
Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…
Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. 其实最简单的就是想到就是用一个小顶堆实现,如果堆中元素个数小于K,则插入元素,如果大于K,则和堆顶比较,如果大于堆顶,则弹出堆顶,插入新元素. 自己实现红黑树有点难,好在C++ STL容器中,map,set和priority_queue都…
Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must be bet…