PAT 1104 Sum of Number Segments】的更多相关文章

Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence {0.1, 0.2, 0.3, 0.4}, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3, 0…
1104. Sum of Number Segments (20) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CAO, Peng Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence {0.1, 0.2, 0.3, 0.4}, we…
本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90486252 1104 Sum of Number Segments (20 分)   Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence { 0.1, 0.2, 0.…
题目链接 https://www.patest.cn/contests/pat-a-practise/1104 思路 最容易想到的一个思路就是 遍历一下所有组合 加一遍 但 时间复杂度 太大 会超时 其实可以发现 每个数字的出现频率是有规律的 比如 4 0.1 0.2 0.3 0.4 这组数据 0.1 4 0.2 6 0.3 6 0.4 4 然后 出现次数 刚好满足 (i + 1) * (n - i) 这个公式 AC代码 #include <cstdio> #include <cstri…
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; int n; +]; +]; ; int main() { scanf("%d&qu…
#include <iostream> #include <cstdio> #include <algorithm> #include <string.h> using namespace std; /* 对于第i个数字(i=0~n-1),它每组出现的次数为n-i,出现在前i+1个组中 */ +; double num[maxn]; int main() { int n; scanf("%d",&n); double sum=0.…
题意:输入一个正整数N(<=1e5),接着输入N个小于等于1.0的正数,输出N个数中所有序列的和. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; int main(){ //ios::sync_with_stdio(false); //cin.tie(NULL); //cout.tie(NULL); int n; scanf("%d&…
Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence { 0.1, 0.2, 0.3, 0.4 }, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3,…
Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence { 0.1, 0.2, 0.3, 0.4 }, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3,…
题意: 给出n个不大于1.0的小数序列,如{ 0.1, 0.2, 0.3, 0.4 },则共有10个分片(0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3, 0.4) (0.3) (0.3, 0.4) and (0.4).现要求计算每个分片之和,即0.1 + 0.3 + 0.6 + 1.0 + 0.2 + 0.5 + 0.9 + 0.3 + 0.7 + 0.4 = 5.0. 思路:数学题…