题意:给出一棵带权无向树,以及给定节点1,总约束为$m$,找出切断与所有叶子节点联系每条边所需要的最小价值约束. 解题关键:二分答案,转化为判定性问题,然后用树形dp验证答案即可. dp数组需要开到ll,如果用设inf的解法. #include<bits/stdc++.h> using namespace std; typedef long long ll; ; const int inf=0x3f3f3f3f; struct edge{ int to; int nxt; int w; }e[…
题目链接 hdu3586 题解 二分 + 简单的树形dp 我正有练一下dp的必要了 #include<iostream> #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> #define LL long long int #define Redge(u) for (int k = h[u],to; k; k = ed[k].nxt) #define REP…
Information Disturbing Problem Description In the battlefield , an effective way to defeat enemies is to break their communication system.The information department told you that there are n enemy soldiers and their network which have n-1 communica…
