1 要解决的问题 计算x*y + z?其中x.y.z都是浮点数. 2 普通的计算方式 e=3; s=4.734612 × e=5; s=5.417242 ----------------------- e=8; s=25.648538980104 (true product) e=8; s=25.64854 (after rounding) e=9; s=2.564854 (after normalization) 在normalization之后,再去加z,得到的结果再进行一次rounding…

Go 1.9 Release Notes Introduction to Go 1.9 Changes to the language Ports ppc64x requires POWER8 FreeBSD OpenBSD 6.0 Known Issues Tools Parallel Compilation Vendor matching with ./... Moved GOROOT Compiler Toolchain Assembler Doc Env Test Pprof Vet G…

The Go Programming Language Specification go语言规范 Version of May 9, 2018 Introduction 介绍 Notation 符号 Source code representation 源代码表示形式 Characters 字符 Letters and digits 字母和数字 Lexical elements 词法元素 Comments 评论 Tokens 令 牌 Semicolons 分号 Identifiers 标识符 K…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

http://anandtech.com/show/2549 Now that NVIDIA’s has announced its newest GPU architecture (the GeForce GTX 200 series), interesting architectural details are popping up on the web. The best writeup I’ve found is by AnandTech. In the past, such detai…

SSE 概述 SSE(Streaming SIMD Extensions)是英特尔在AMD的3D Now!发布一年之后,在其计算机芯片Pentium III中引入的指令集,是MMX的超集.AMD后来在Athlon XP中加入了对这个指令集的支持.这个指令集增加了对8个128位寄存器XMM0-XMM7的支持,每个寄存器可以存储4个单精度浮点数.使用这些寄存器的程序必须使用FXSAVE和FXRSTR指令来保持和恢复状态.但是在Pentium III对SSE的实现中,浮点数寄存器又一次被新的指令集占用…

unit untCpuInfo;interface{ 获取 CPU 制造商 }function GetCpuFactory: String;{ 获取 CPU 家族系统 }function GetCpuFamily: Cardinal;{ 获取 CPU 型号 }function GetCpuModel: Cardinal;{ 获取 CPU 步进 }function GetCpuStepping: Cardinal;{ 获取 CPU 名称 }function GetCpuName: String;{…