pro:给定规则的多边形,规则是指顶点都在整点上,而且是相互垂直的边的交点. 现在给定两个多边形A,B,问A,B缩小,旋转后是否可以变为同一个图形. sol:缩小的话,直接离散化即可,就可以去掉没用的部分,旋转的话,可以手动旋转4次. #include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<=b;i++) using namespace std; ; struct in{ int N,a[maxn],b[maxn],x[maxn]…

E. Mike and Geometry Problem 题目连接: http://www.codeforces.com/contest/689/problem/E Description Mike wants to prepare for IMO but he doesn't know geometry, so his teacher gave him an interesting geometry problem. Let's define f([l, r]) = r - l + 1 to…

一.Geometry转WKT select st_astext(geom) where tableName; 二.PostGIS常用函数 wkt转geometry st_geomfromtext(wkt,wkid) geometry转wkt st_astext(geom) 获取点对象x.y坐标值 st_x(geom).st_y(geom) 获取线/面对象四至 st_xmin(geom).st_ymin(geom).st_xmax(geom).st_ymax(geom) 计算两点之间距离 st_d…

E. Mike and Geometry Problem time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Mike wants to prepare for IMO but he doesn't know geometry, so his teacher gave him an interesting geometry pro…

geometry属性保存部件相对于其父级对象的位置和大小,Qt实际上是以一个长方形来表示部件的位置和大小的,包括左上角的坐标位置.长度和宽带. 当部件的geometry调整时,部件如果可见将立即接收moveEvent事件和/或调整大小的resizeEvent事件.如果部件当前不可见,则Qt保证它在显示之前接收适当的事件. 如果部件的geometry被要求调整到超出minimumSize()和maximumSize()定义的范围之外时,则Qt会强制部件的大小必须在minimumSize()和max…

E. Polish Fortress time limit per test 2.0 s memory limit per test 256 MB input standard input output standard output The Malbork castle is the largest brick castle in the world. It was built in 1274 in honor to Holy Mary, and is located near the riv…

题意:你从开始坐标到末尾坐标,要经过 k 秒,然后给你每秒的风向,和飞机的最大速度,问能不能从开始到末尾. 析:首先这个风向是不确定的,所以我们先排除风向的影响,然后算出,静风是的最小速度,如果这都大于最大速度,肯定是不可能,如果可能, 再计算出每秒走的单位长度,然后再模拟整个过程. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <str…

原文链接:http://blog.csdn.net/cdl2008sky/article/details/7268577 空间数据模型(1).JTS Geometry model (2).ISO Geometry model (Geometry Plugin and JTS Wrapper Plugin)GeoTools has two implementations of these interfaces:Geometry Plugin a port of JTS 1.7 to the ISO…

WKT定义几何对象格式: POINT(0 0) ——点 LINESTRING(0 0,1 1,1 2) ——线 POLYGON((0 0,4 0,4 4,0 4,0 0),(1 1, 2 1, 2 2, 1 2,1 1)) ——面 MULTIPOINT(0 0,1 2) ——多点 MULTILINESTRING((0 0,1 1,1 2),(2 3,3 2,5 4)) ——多线 MULTIPOLYGON(((0 0,4 0,4 4,0 4,0 0),(1 1,2 1,2 2,1 2,1 1)),…

Gym 101482C Cent Savings 简单的dp #include<bits/stdc++.h> #define inf 0x3f3f3f3f #define inf64 0x3f3f3f3f3f3f3f3f using namespace std; typedef long long ll; const int maxn=2200; ll dp[maxn][22],sum[maxn]; int main(){ int n,m; scanf("%d%d",&am…