NOJ 1651 Red packet(二分)】的更多相关文章

[1651] Red packet 时间限制: 1000 ms 内存限制: 65535 K 问题描述 New Year is coming! Our big boss Wine93 will distribute some “Red Package”, just like Alipay and Wechat. Wine93 has m yuan, he decides to distribute them to n people and everyone can get some money(0…
Description New Year is coming! Our big boss Wine93 will distribute some “Red Package”, just like Alipay and Wechat. Wine93 has m yuan, he decides to distribute them to n people and everyone can get some money(0 yuan is not allowed and everyone’s mon…
新年抢红包效果(New Year Red Packet) 晓娜的文章(微信公众号:migufe) 2016即将过去,我们将迎来新的一年2017,这里小编提前祝大家新年快乐!万事如意!那我们新年最开心的事是什么呢,没错,我想要说的就是“抢红包”,家人群,朋友群,同事群,新年如果不抢几个红包,那真是好像失去了天大的乐趣. 下面我就分享一个简单的拆红包特效,最终结果就是下图: 代码实现: HTML代码部分 HTML代码比较简单,短短几行代码就全部可以搞定. CSS代码部分 因为本身红包就图个喜庆,颜色…
[1649] Find Sum 时间限制: 1000 ms 内存限制: 65535 K 问题描述 This problem is really boring. You are given a number sequence S which contain n integers and m queries, each time i will give your two integers id1 and id2, you need to tell me whether i can get S[id1…
http://www.iocoder.cn/categories/TCC-Transaction/ https://github.com/changmingxie/tcc-transaction 细读tcc,理解事物实现的本质 顾名思义,TCC - Try(完成所有业务检查,预留必须业务资源) ,Confirm(真正执行业务,不做任何业务检查,只使用Try阶段预留的业务资源,Confirm操作满足幂等性),Cancel(释放Try阶段预留的业务资源,cancel操作满足幂等性) 觉得应该先看下上…
arg对应多出来的位置参数,把它们解析成tuple;kwargs把关键字参数解析成dict. def example(pram): print(pram) def example2(param, *args, **kwargs): print(param) if args: print(args) if kwargs: print(kwargs) #一个不设定参数个数的加法函数 def sum(*args): sum = 0 for a in args: sum += a return sum…
<?php namespace app\common\controller; use think\Controller; use think\Db; class Csv extends Controller { public static function putCsv($condition, $action, $file_name) { set_time_limit(0); switch ($action) { case "web": $field = [ 'A' =>…
想了想自己留的坑有点多了,写个计划提醒自己 一些没做出来的题 csp-s模拟测试54 z csp-s模拟测试b层加餐 string 平衡树+并查集 因为某杰的**安排,没时间改了csp-s模拟测试47 字符消除2 KMPcsp-s模拟测试45 weight 树链剖分,最小生成树csp-s模拟测试43 B 神仙DP????csp-s模拟测试42 密码 数学??NOIP模拟测试38 赤(red) wqs二分......大概坑还很多........ 一些杂题 1.消防(树上直径) 2.SZN 3.期末…
二分查找: 要么左边,要么右边,哈哈哈哈 描述 给定一个单调递增的整数序列,问某个整数是否在序列中.   输入 第一行为一个整数n,表示序列中整数的个数:第二行为n(n不超过10000)个整数:第三行为一个整数m(m不超过50000),表示查询的个数:接下来m行每行一个整数k.   输出 每个查询的输出占一行,如果k在序列中,输出Yes,否则输出No.   输入样例 51 3 4 7 113369   输出样例 YesNoNo 代码实现如下: #include <stdio.h> int n;…
[1274] The battle of Red Cliff 时间限制: 1000 ms 内存限制: 65535 K 问题描述 Zero loves palying Sanguo game very much, The battle of Red Cliff is one of scenes. Now he will put a fire to one of ships. Some ships are connected, some are not.Now, zero puts his fire…