题意 Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. 给定数字,输出所有可能的字母组合 解法 可以先将数字对应的字母存好,然后遍历输出就可以.只不过不用递归来写好像比较麻烦,这里用了一个DFS…

Letter Combinations of a Phone Number Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input:Digit string "23"Output…

Letter Combinations of a Phone Number: Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input:Digit string "23" Outp…

Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input:Digit string "23" Output: ["ad", "ae", &q…

Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input: Digit string "23" Output: ["ad", "ae", &…

Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input:Digit string "23" Output: ["ad", "ae", &q…

Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input:Digit string "23" Output: ["ad", "ae", &q…

Given a digit string, return all possible letter combinations that the number could represent. A mapping of digit to letters (just like on the telephone buttons) is given below. Input:Digit string "23" Output: ["ad", "ae", &q…

题意:给一个电话号码,要求返回所有在手机上按键的组合,组合必须由键盘上号码的下方的字母组成. 思路:尼玛,一直RE,题意都不说0和1怎么办.DP解决. class Solution { public: vector<string> ans; string str; void DFS(const string sett[], int siz, string t ) { '; if(siz==str.size()){ans.push_back( t );return ;} ; i<sett[…

class Solution(object): def letterCombinations(self, digits): """ :type digits: str :rtype: List[str] """ if len(digits) <= 0: return list() alpha = [","abc","def","ghi","jkl",&…