Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 单调递减栈 日期 题目地址:https://leetcode.com/problems/online-stock-span/description/ 题目描述 Write a class StockSpanner which collects daily price quotes for some stock, and returns the spa…

Span 指这个元素之前连续的小于这个元素的值有多少个 原理: 维护递减栈 这个栈内的元素是递减的序列 新到一个元素x 依次出栈比x小的(也就是这个元素的Span) 这种问题的关键在于 新来的元素如果比前一个元素小 那么答案是1 如果比前一个元素大 ( 那么前一个元素在之后就完全没有用了, 所以可以出栈, 使用现有的元素进行意义的记录 ) 相关题目 Unique Letter String Sum of Subsequence Widths 907 907是求一个双向的Span 但是有一个重复元…

题目如下: 解题思路:和[leetcode]84. Largest Rectangle in Histogram的核心是一样的,都是要找出当前元素之前第一个大于自己的元素. 代码如下: class StockSpanner(object): def __init__(self): self.cl = [] self.vl = [] def next(self, price): """ :type price: int :rtype: int """…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

2018-11-16 22:45:48 一.单调队列 Monotone Queue 239. Sliding Window Maximum 问题描述: 问题求解: 本题是一个经典的可以使用双端队列或者说单调队列完成的题目,具体来说,就是通过双端队列将可能的最大值维护起来. public int[] maxSlidingWindow(int[] nums, int k) { if (nums == null || nums.length < k || k == 0) return new int[…

堆栈基础 堆栈(stack)具有“后进先出”的特性,利用这个特性我们可以用堆栈来解决这样一类问题:后续的输入会影响到前面的阶段性结果.线性地遍历输入并用stack处理,这类问题较简单,求解时间复杂度一般为O(n). 相关LeetCode题: 13. Roman to Integer  题解 20. Valid Parentheses  题解 844. Backspace String Compare  题解 1047. Remove All Adjacent Duplicates In Stri…