题目描述 找出字符串中第一个只出现一次的字符 如果无此字符 请输出'.' 输入描述: 输入一串字符,由小写字母组成 输出描述: 输出一个字符 输入例子: asdfasdfo 输出例子: o 思路:数组s记录出现的字母顺序.time数组记录出现的次数,每个char对应一个int型,,,所以,字母a出现的次数可以直接用time['a']表示. AC代码: #include "iostream" #include "string.h" #define MAX 201 us…

如题~ 此算法仅供参考,小菜基本不懂高深的算法,只能用最朴实的思想去表达. //找出字符串中第一个不重复的字符 // firstUniqueChar("vdctdvc"); --> t function firstUniqueChar(str){ var str = str || "", i = 0, k = "", _char = "", charMap = {}, result = {name: "&quo…

面试题35:第一个只出现一次的字符 题目:在一个字符串中找到第一个只出现一次的字符.如输入abaccdeff,则输出b.(2006年google的一道笔试题.) 分析: 首先应向确认一下是ASCII字符串,而不是Unicode字符串.用hash表求解即可,由于需要先遍历一次,时间复杂度为O(n),空间复杂度为O(1) (256个ASCII字符). 满足题意的代码如下: #include<cstdio> #include<string> #include<unordered_m…

Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100. The order of output does not matter.…

Input: s: "abab" p: "ab" Output: [0, 1, 2] Explanation: The substring with start index = 0 is "ab", which is an anagram of "ab". The substring with start index = 1 is "ba", which is an anagram of "ab&…

一.循环obj let testStr = 'asdasddsfdsfadsfdghdadsdfdgdasd'; function getMax(str) { let obj = {}; for(let i in str) { if(obj[str[i]]) { obj[str[i]]++; }else{ obj[str[i]] = 1; } } let keys = Object.keys(obj); // 获取对象中所有key的值返回数组 let values = Object.values…

可以通过写自定义函数实现,以下提供两种思路来解决: 1.通过正则匹配,找到字符串中的数字,一个一个拼起来 /*方法一: 一个一个找出来*/ CREATE FUNCTION [dbo].[Fun_GetNumPart] ( @Str NVARCHAR(MAX) ) RETURNS NVARCHAR(MAX) AS BEGIN DECLARE @Start INT; DECLARE @End INT; DECLARE @Part NVARCHAR(MAX) SET @Start = PATINDEX…

Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100. The order of output does not matter.…

已知字符串"aabbbcddddeeffffghijklmnopqrst"编程找出出现最多的字符和次数,要求时间复杂度小于O(n^2) /******************************************************** Copyright (C), 2016-2017, FileName: main9 Author: woniu201 Email: wangpengfei.201@163.com Created: 2017/10/31 Descripti…

# 请大家找出s=”aabbccddxxxxffff”中 出现次数最多的字母 # 第一种方法,字典方式: s="aabbccddxxxxffff" count ={} for i in set(s): count[i]=s.count(i) print(count) # print(max(count.items(),key=lambda x:x[1])[0]) max_value=max(count.values()) l=[] for k,v in count.items(): i…