题目描述 Farmer John's N (1 <= N <= 100,000) cows are lined up in a row andnumbered 1..N. The cows are conducting another one of their strangeprotests, so each cow i is holding up a sign with an integer A_i(-10,000 <= A_i <= 10,000). FJ knows the…
2274: [Usaco2011 Feb]Generic Cow Protests Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 196  Solved: 122[Submit][Status] Description Farmer John's N (1 <= N <= 100,000) cows are lined up in a row and numbered 1..N. The cows are conducting another…
Description Farmer John's N (1 <= N <= 100,000) cows are lined up in a row and numbered 1..N. The cows are conducting another one of their strange protests, so each cow i is holding up a sign with an integer A_i (-10,000 <= A_i <= 10,000). FJ…
[题解] 很容易可以写出朴素DP方程f[i]=sigma f[j] (sum[i]>=sum[j],1<=j<=i).  于是我们用权值树状数组优化即可. #include<cstdio> #include<algorithm> #define N 200010 #define rg register #define LL long long #define Mod (1e9+9) using namespace std; int n,n2; LL t[N],f[…
//树形DP+树状数组 HDU 5877 Weak Pair // 思路:用树状数组每次加k/a[i],每个节点ans+=Sum(a[i]) 表示每次加大于等于a[i]的值 // 这道题要离散化 #include <bits/stdc++.h> using namespace std; #define LL long long typedef pair<int,int> pii; const double inf = 123456789012345.0; const LL MOD…
1264: [AHOI2006]基因匹配Match Time Limit: 10 Sec  Memory Limit: 162 MBSubmit: 793  Solved: 503[Submit][Status][Discuss] Description 基 因匹配(match) 卡卡昨天晚上做梦梦见他和可可来到了另外一个星球,这个星球上生物的DNA序列由无数种碱基排列而成(地球上只有4种),而更奇怪的是,组成DNA序列的 每一种碱基在该序列中正好出现5次!这样如果一个DNA序列有N种不同的碱基…
奶牛抗议 DP 树状数组 USACO的题太猛了 容易想到\(DP\),设\(f[i]\)表示为在第\(i\)位时方案数,转移方程: \[ f[i]=\sum f[j]\;(j< i,sum[i]-sum[j]\ge0) \] \(O(n^2)\)过不了,考虑优化 移项得: \[ f[i]=\sum f[j]\;(j< i,sum[i]\ge sum[j]) \] 这时候我们发现相当于求在\(i\)前面并且前缀和小于\(sum[i]\)的所有和,这就可以用一个树状数组优化了,在树状数组维护下标为…
题目链接: C. Subsequences time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2227 Find the nondecreasing subsequences                                  Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)                                             …
题意:给你一个n个数的序列,要求从中找出含m个数的严格递增子序列,求能找出多少种不同的方案 dp[i][j]表示以第i个数结尾,形成的严格递增子序列长度为j的方案数 那么最终的答案应该就是sigma(dp[i][m]); 显然有:dp[i][j] = sigma(dp[k][j - 1]); 其中 1 <= k < i 且 a[k] < a[i]; 题目要求严格递增,这个限制怎么解决? hdu4719这道题同样是这样处理,即我们只需要从小到大dp就行了. 但是复杂度是O(n^3)的,显然…