\(KMP\)问题的核心在于数组\(next\)(或者\(pre\)/\(fail\),各种叫法),几乎所有的此类型题都是需要计算\(next\)的. 这里解释一波\(next\):即满足字符子串\(s[1...k]=s[j-k+1...j]\)的最大\(k\).比如说: 字符串\(abaca\)的\(next[5]\)就是\(1\),因为只有\(s[1]=s[5]\). 而字符串\(abcab\)的\(next[5]\)就是2,同理,\(s[1...2]=s[4...5]\). 弄清楚了这一点…

Censoring Time Limit: 10 Sec  Memory Limit: 128 MB[Submit][Status][Discuss] Description 有一个S串和一个T串,长度均小于1,000,000,设当前串为U串,然后从前往后枚举S串一个字符一个字符往U串里添加,若U串后缀为T,则去掉这个后缀继续流程. Input 第一行是S串,第二行是T串. Output 输出一行,表示按照操作后得到的串. Sample Input whatthemomooofun moo Sa…

3942: [Usaco2015 Feb]Censoring Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the late…

3942: [Usaco2015 Feb]Censoring Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 375  Solved: 206[Submit][Status][Discuss] Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material…

问题描述 LG4824 题解 大概需要回顾(看了题解) KMP 先对要删除的 模式串 进行自我匹配,求出 \(\mathrm{fail}\) 然后再扫 文本串 的过程中记录一下每个字符匹配的最大长度,用栈进行删除. 这类删除一段连续区间的问题常用栈来优化维护 \(\mathrm{Code}\) #include<bits/stdc++.h> using namespace std; template <typename Tp> void read(Tp &x){ x=0;c…

[题目大意] 有一个匹配串和多个模式串,现在不断删去匹配串中的模式串,求出最后匹配串剩下的部分. [思路] 众所周知,KMP的题往往对应着一道AC自动机quq.本题同BZOJ3942(KMP),这里改成AC自动机即可. 我一开始写了原始的AC自动机,写挂了.后来思考了一下,应当用Trie图,机智地1A. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #inc…

[BZOJ3942][Usaco2015 Feb]Censoring Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the…

Description Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest issue contains a rather inap…

[KMP]Censoring 题目描述 Farmer John has purchased a subscription to Good Hooveskeeping magazine for his cows, so they have plenty of material to read while waiting around in the barn during milking sessions. Unfortunately, the latest issue contains a rat…

# 10048. 「一本通 2.2 练习 4」Censoring [题目描述] 给出两个字符串 $S$ 和 $T$,每次从前往后找到 $S$ 的一个子串 $A=T$ 并将其删除,空缺位依次向前补齐,重复上述操作多次,直到 $S$ 串中不含 $T$ 串.输出最终的 $S$ 串. [算法] 1.kmp $O(n)$就可以定位. 2.栈是个好东西啊. 注:一开始想双指针,实在不好写...栈很好,它可以弹出去...(此处滑稽脸) [代码] #include <bits/stdc++.h> using…