1046. 最后一块石头的重量 1046. Last Stone Weight 题目描述 每日一算法2019/6/22Day 50LeetCode1046. Last Stone Weight Java 实现 and so on 参考资料 https://leetcode.com/problems/last-stone-weight/ https://leetcode-cn.com/problems/last-stone-weight/…
原题链接在这里:https://leetcode.com/problems/last-stone-weight/ 题目: We have a collection of rocks, each rock has a positive integer weight. Each turn, we choose the two heaviest rocks and smash them together. Suppose the stones have weights x and y with x…
有一堆石头,每块石头的重量都是正整数. 每一回合,从中选出两块最重的石头,然后将它们一起粉碎.假设石头的重量分别为 x 和 y,且 x <= y.那么粉碎的可能结果如下: 如果 x == y,那么两块石头都会被完全粉碎:如果 x != y,那么重量为 x 的石头将会完全粉碎,而重量为 y 的石头新重量为 y-x.最后,最多只会剩下一块石头.返回此石头的重量.如果没有石头剩下,就返回 0. 提示: 1 <= stones.length <= 301 <= stones[i] <…
leetcode真的是一个学习阅读理解的好地方 860. 柠檬水找零 """ 因为用户支付的只会有5.10.20 对于10元的用户必须找一个5 对于20元的用户可以找(三个5)或者(一个10一个5),每次都从大的开始找起来 """ class Solution: def lemonadeChange(self, bills) -> bool: five = 0 ten = 0 for i in bills: if i == 5: five…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 大根堆 日期 题目地址:https://leetcode.com/problems/last-stone-weight/ 题目描述 We have a collection of rocks, each rock has a positive integer weight. Each turn, we choose the two heaviest…
题目如下: We have a collection of rocks, each rock has a positive integer weight. Each turn, we choose the two heaviest rocks and smash them together. Suppose the stones have weights x and y with x <= y. The result of this smash is: If x == y, both sto…
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