1018 Public Bike Management (30 分)   There is a public bike service in Hangzhou City which provides great convenience to the tourists from all over the world. One may rent a bike at any station and return it to any other stations in the city. The Pub…

时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue There is a public bike service in Hangzhou City which provides great convenience to the tourists from all over the world. One may rent a bike at any station and return it to any othe…

时间限制400 ms 内存限制65536 kB 代码长度限制16000 B There is a public bike service in Hangzhou City which provides great convenience to the tourists from all over the world. One may rent a bike at any station and return it to any other stations in the city. The Pu…

题目 There is a public bike service in Hangzhou City which provides great convenience to the tourists from all over the world. One may rent a bike at any station and return it to any other stations in the city. The Public Bike Management Center (PBMC)…

There is a public bike service in Hangzhou City which provides great convenience to the tourists from all over the world. One may rent a bike at any station and return it to any other stations in the city. The Public Bike Management Center (PBMC) kee…

题目 There is a public bike service in Hangzhou City which provides great convenience to the tourists from all over the world. One may rent a bike at any station and return it to any other stations in the city. The Public Bike Management Center (PBMC)…

https://www.patest.cn/contests/pat-a-practise/1018 先用Dijkstra算出最短路,然后二分答案来验证,顺便求出剩余最小,然后再从终点dfs回去求出路径 #include<cstdio> #include<string> #include<cstring> #include<vector> #include<iostream> #include<queue> #include<a…

前言: 本题是我在浏览了柳神的代码后,记下的一次半转载式笔记,不经感叹柳神的强大orz,这里给出柳神的题解地址:https://blog.csdn.net/liuchuo/article/details/52316405 题意: 有一个租借自行车的系统由n个点组成,用户可以在这n个点任意一个点借车或者还车,每个点都遵循一个共同的上限c,这里我们称一个点的状态时完美的如果这个点的车的数量为c/2,(每个点由1~n标号),而我们的出发点为0点,整个系统每次会有一个sp点发出警报,说明这个sp点的自行…

先找出可能在最短路上的边,图变成了一个DAG,然后在新图上DFS求答案就可以了. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<queue> #include<vector> using namespace std; const int INF=0x7FFFFFFF; ;…

题目及题解 https://blog.csdn.net/CV_Jason/article/details/81385228 迪杰斯特拉重新认识 两个核心的存储结构: int dis[n]: //记录每个点到源头的最短距离 bool mark[n]; //标记每个顶点到 /*如果想要保存路径,创建一个 二维数组,或者vector[n], 里面的每个一维数组表示到达该节点的前一个节点,在(u为当前选出的新节点)当dis[v]==dis[u]+e[u][v],说明通过u到达v的路径也是最短路径,于是把…