偶数求和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 45262 Accepted Submission(s): 19773 Problem Description 有一个长度为n(n<=100)的数列,该数列定义为从2开始的递增有序偶数,现在要求你按照顺序每m个数求出一个平均值,如果最后不足m个,则以实际数量求平均值.编程输…
偶数求和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 120940 Accepted Submission(s): 50025 Problem Description 有一个长度为n(n<=100)的数列,该数列定义为从2开始的递增有序偶数,现在要求你按照顺序每m个数求出一个平均值,如果最后不足m个,则以实际数量求平均值.编程输…
题目地址 :多项式求和 /* #include<stdio.h> int main() { int n,b; double a[110],x; double z; int i,j; int f; for (i=1;i<101;i++) a[i]=(double)1/(double)i; scanf("%d",&n); while(n--) { scanf("%d",&b); z = 0; f = 1; //printf("…
最近在尝试做acm试题,刚刚是1001题就把我困住了,这是题目: Problem Description In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n. Input The input will consist of a series of integers n, one integer per line Output For each case, output SUM(n) in one…
杭电ACM(1002)大数相加 A + B Problem II Problem DescriptionI have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B. InputThe first line of the input contains an integer T(1<=T<=20) which means the number…
