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http://codeforces.com/contest/747/problem/F cf #387 div2 problem f 非常好的一道题.看完题,然后就不知道怎么做,感觉是dp,但是不知道怎么枚举.还有就是一般求第k小的思路一般是什么?对这类题目理解的不是很好. 这道题,跟上一篇的题解里面写的hdu 1002 递增数的题目的解法差不多,但是底层的求解需要花一些时间去推敲! 不会做,就看官方题解,看不懂说的什么.就从下面的讨论找大神的题解. I can describe my solu…
我佛了,这CF居然没有官方题解. 题意:给定k,t,求第k小的16进制数,满足每个数码的出现次数不超过t. 解: 每个数都有个出现次数限制,搞不倒.一开始想到了排序hash数位DP,不过写了写觉得不胜其烦,就弃疗了. 但是思考一下,如果我们知道了每个数的出现次数和数的位数,那么一次普通DP就能够求出方案数. 所以我们暴力做多次这种普通DP即可...... 具体来说,分为带前导0和不带前导0两个DP函数. 首先枚举数的长度,计算不带前导0的个数.如果不到k就减去. 然后知道了长度,再一位一位的确定…
题意:给你一个数n和t,问字母出现次数不超过t,第n小的16进制数是多少. 思路:容易联想到数位DP, 然而并不是...我们需要知道有多少位,在知道有多少位之后,用试填法找出答案.我们设dp[i][j]为考虑前i种字母,已经占了j个位置的方案数.那么dp[i][j] += dp[i - 1][j - k] * C[len - j + k][k],k的范围为[0, limit[k]].意思是我们暴力枚举第i个字母放多少个,然后排列组合. 这个题有一个细节需要注意,因为最高为一定不为0,所以我们试填…
2070. Interesting Numbers Time limit: 2.0 secondMemory limit: 64 MB Nikolay and Asya investigate integers together in their spare time. Nikolay thinks an integer is interesting if it is a prime number. However, Asya thinks an integer is interesting i…
目录 1 问题描述 2 解决方案   1 问题描述 Problem Description We call a number interesting, if and only if: 1. Its digits consists of only 0, 1, 2 and 3, and all these digits occurred at least once. 2. Inside this number, all 0s occur before any 1s, and all 2s occur…
1 问题描述 Problem Description We call a number interesting, if and only if: 1. Its digits consists of only 0, 1, 2 and 3, and all these digits occurred at least once. 2. Inside this number, all 0s occur before any 1s, and all 2s occur before any 3s. The…
链接:https://ac.nowcoder.com/acm/contest/338/F来源:牛客网 题目描述 AFei loves numbers. He defines the natural number containing "520" as the AFei number, such as 1234520, 8752012 and 5201314. Now he wants to know how many AFei numbers are not greater than…
Description xrdog has a number set. There are 95 numbers in this set. They all have something in common and are all positive integers less than 500. The naughty xiao zhuan has deleted one of the numbers in the set. Can you find the number that xiao z…
题意:在[L, R]之间求:x是个素数,因子个数是素数,同时满足两个条件,或者同时不满足两个条件的数的个数. 析:很明显所有的素数,因数都是2,是素数,所以我们只要算不是素数但因子是素数的数目就好,然后用总数减掉就好.打个表,找找规律,你会发现, 这些数除外的数都是素数的素数次方,然后就简单了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include &…
素数必然符合题意. 对于合数,如若它是某个素数x的k次方(k为某个素数y减去1),一定不符合题意.只需找出这些数. 由约数个数定理,其他合数一定符合题意. 就从小到大枚举素数,然后把它的素数-1次方都排除即可. #include<cstdio> #include<cmath> using namespace std; #define MAXP 1000100 #define EPS 0.00000001 typedef long long ll; ll L,R; bool isNo…