题目描述: Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 解题思路: 把除数表示为:dividend = 2^i * divisor + 2^(i-1) * divisor + ... + 2^0 * divisor.这样一来,我们所求的商就是各系数之和了,而每个系数都可以通过移位操作获得. 详细解说请参考:http:/…

Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend…

  Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: divide…

转载:https://blog.csdn.net/Lynn_Baby/article/details/80624180 Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer divi…

Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend…

Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 解法: 这道题让我们求两数相除,而且规定我们不能用乘法,除法和取余操作. 采用位运算中的移位运算,左移一位相当于乘2,右移一位相当于除以2.假设求 a / b,将b左移n位后大于a,则结果 res += 1 << (n - 1),将a更新 (a -= b <<…

Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend…

这道题目一直不会做,因为要考虑的corner case 太多. 1. divisor equals 0. 2. dividend equals 0. 3. Is the result negative? 4. when dividend equals Integer.MIN_VALUE and divisor equals -1, the result will overflow. convert result to long and then to integer. 5. have to us…

题目链接: https://leetcode.com/problems/divide-two-integers/?tab=Description   Problem :不使用乘法,除法,求模计算两个数的除法~   除法运算:被除数中包含有多少个除数的计算   由于是int类型的除法,因此结果可能超过int的最大值,当超过int的最大值时输出int的最大值   另写除法函数,计算出除法的商. 首先判断出除法运算后的结果是正数还是负数. 之后需要将被除数和除数都变为正数,进行进一步计算 当被除数小于…

1. 原题链接 https://leetcode.com/problems/divide-two-integers/description/ 2. 题目要求 给出被除数dividend和除数divisor,求出二者相除的商,余数忽略不计. 注意:不能使用乘法.除法和取余运算 3. 解题思路 陷阱一:MIN_VALUE/-1会溢出.因为Integer.MIN_VALUE = -的绝对值比Integer.MAX_VALUE大1 陷阱二:除数divisor不能等于“0” 思路一:使用一个while循环…