219. Contains Duplicate II[easy] Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. 错误解法: class Solut…

Question 219. Contains Duplicate II Solution 题目大意:数组中两个相同元素的坐标之差小于给定的k,返回true,否则返回false 思路:用一个map记录每个数的坐标,如果数相同,如果坐标差小于k则返回true否则覆盖,继续循环 Java实现: public boolean containsNearbyDuplicate(int[] nums, int k) { Map<Integer, Integer> map = new HashMap<&…

每天一算:Contains Duplicate II 描述 给出1个整形数组nums和1个整数k,是否存在索引i和j,使得nums[i] == nums[j] 且i和j之间的差不超过k Example 1: Input: nums = [1,2,3,1], k = 3 Output: true. Example 2: Input: nums = [1,0,1,1], k = 1 Output: true Example 3: Input: nums = [1,2,3,1,2,3], k = 2…

Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. Example 1: Input: nums = [1,2,3,1], k = 3 Output:…

要求 给出整型数组nums和整数k,是否存在索引i和j,nums[i]==nums[j],且i和j之间的差不超过k 思路 暴力解法(n2) 建立最长为k+1的滑动窗口,用set查找窗口中是否有重复元素,若没有则向后滑动(时间n,空间k) 并不存在滑动窗口的实体,通过维护set中的元素实现 代入具体例子确定边界 1 class Solution { 2 public: 3 bool containsNearbyDuplicate(vector<int>& nums, int k) { 4…

Problem: Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. Summary: 给出数组nums,整型数k,找到数组中是否存在nums[i]和nums[j]相等且…

Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. 解题思路: HashMap,JAVA实现如下: public boolean containsNearby…

找出是否存在nums[i]==nums[j],使得 j - i <=k 这是map的一个应用 class Solution { public: bool containsNearbyDuplicate(vector<int>& nums, int k) { map<int,int> mii; ;i<nums.size() ;++i) { if (mii.find(nums[i]) != mii.end()) { if(i - mii[nums[i]] <=…

#-*- coding: UTF-8 -*-#遍历所有元素,将元素值当做键.元素下标当做值#存放在一个字典中.遍历的时候,#如果发现重复元素,则比较其下标的差值是否小于k,#如果小于则可直接返回True,否则更新字典中该键的值为新的下标class Solution(object):    def containsNearbyDuplicate(self, nums, k):        """        :type nums: List[int]        :typ…

Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between iand j is at most k. 方法1:暴力解法 代码如下: public class Solution { public boolean…