hdu 4658 Integer Partition】的更多相关文章

题目:http://acm.hdu.edu.cn/showproblem.php?pid=4651 参考:https://blog.csdn.net/u013007900/article/details/42365823 https://blog.csdn.net/visit_world/article/details/52734860 好像这样复杂度就是 \( O(n\sqrt{n} \) 的了. #include<cstdio> #include<cstring> #inclu…
Integer Partition Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 22    Accepted Submission(s): 15 Problem Description Given n, k, calculate the number of different (unordered) partitions of n s…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4658 题意:给出n.k.求n的拆分方案数.要求拆分中每个数不超过k. i64 f[N]; void init(){    f[0]=f[1]=1; f[2]=2;    int i,j,k,t;    for(i=3;i<N;i++) for(j=1;;j++)    {        FOR0(k,2)        {            if(!k) t=(3*j*j-j)/2;     …
五角数定理!!可以参考这个http://www.cnblogs.com/xin-hua/p/3242428.html  代码如下: #include<iostream> #include<stdio.h> #include<algorithm> #include<iomanip> #include<cmath> #include<string> #include<vector> #define ll __int64 #de…
hdu 4658 Integer Partition 题意 n分拆成若干个正整数的和,每个正整数出现小于k次,分拆方案有多少.(t<=100,n<=1e5) 题解 之前写过一篇Partition Numbers的计算,后面补充了hdu 4651的做法.就是利用五边形数定理. 这题加强了限制条件. n的无序分拆数的生成函数: \(\sum_{i=1}^{\infty}B(i)x^i=(1+x+x^2+..)(1+x^2+x^4+..)-=\frac {1}{\prod_{i=1}^{\infty…
Integer Partition Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 524 Accepted Submission(s): 238 Problem Description Given n, k, calculate the number of different (unordered) partitions of n such…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1047 Integer Inquiry Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of t…
Integer’s Power Time Limit: 1000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 320864-bit integer IO format: %I64d      Java class name: Main   LMY and YY are number theory lovers. They like to find and solve some interesti…
Integer Inquiry Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11678    Accepted Submission(s): 2936 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He ex…
Problem Description Oneof the first users of BIT's new supercomputer was Chip Diller. He extended hisexploration of powers of 3 to go from 0 to 333 and he explored taking varioussums of those numbers.  ``This supercomputer is great,'' remarked Chip.…