Geometric Progression Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://bestcoder.hdu.edu.cn/contests/contest_chineseproblem.php?cid=628&pid=1001 Description 判断一个数列是否为等比数列. 在数学中,等比数列,是一个数列,这个数列中的第一项之后的每一项是前一项乘上一个固定的非零实数(我们称之为公比).比如,数列 2, 6, 18, 54,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5429 题意:给一段长度不超过100的每个数字(可以是浮点数)的长度不超过1000的序列,问这个序列是否是一个等比数列: 等比数列以第一个数为首项,并且r != 0,一个坑点 之前我写的hdu1002的高精度在这里不能用的,因为我的高精度里面还只能是正整数,这时直接使用java的BigDecimal即可: ps:特别要注意 1 0这个序列不是等比序列!还有 大数比较是否相等,要使用函数,不能使用==,…

Problem Description Determine whether a sequence is a Geometric progression or not. In mathematics, a **geometric progression**, also known , , , , ... . Similarly , , /. Examples of a geometric sequence are powers rk of a fixed number r, such as 2k…

题意:给出一个大数数列,问是不是等比数列. 解法:拿java大数搞,注意全是0的情况也是Yes.我把公比用分数表示了,灰常麻烦,题解说只要判a[i - 1] * a[i + 1] == a[i] * a[i]就可以了,涨姿势了. 代码: import java.math.*; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin = new Scanne…

C. Geometric Progression Time Limit: 2 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/567/problem/C Description Polycarp loves geometric progressions very much. Since he was only three years old, he loves only the progressions of length…

Geometric Progression Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 567C Description Polycarp loves geometric progressions very much. Since he was only three years old, he loves only t…

C. Geometric Progression time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Polycarp loves geometric progressions very much. Since he was only three years old, he loves only the progressions o…

题目链接:http://codeforces.com/problemset/problem/567/C C. Geometric Progression time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Polycarp loves geometric progressions very much. Since he was on…

题目传送门 /* 题意:问选出3个数成等比数列有多少种选法 map:c1记录是第二个数或第三个数的选法,c2表示所有数字出现的次数.别人的代码很短,思维巧妙 */ /************************************************ * Author :Running_Time * Created Time :2015-8-6 1:07:18 * File Name :C.cpp *******************************************…

time limit per test : 1 second memory limit per test : 256 megabytes input : standard input output : standard output Problem Description Polycarp loves geometric progressions very much. Since he was only three years old, he loves only the progression…