Query on The Trees Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 6447    Accepted Submission(s): 2547 Problem Description We have met so many problems on the tree, so today we will have a que…

Problem Description We have met so many problems on the tree, so today we will have a query problem on a set of trees.There are N nodes, each node will have a unique weight Wi. We will have four kinds of operations on it and you should solve them eff…

人生的第一道动态树,为了弄懂它的大致原理,需要具备一些前置技能,如Splay树,树链剖分的一些概念.在这里写下一些看各种论文时候的心得,下面的代码是拷贝的CLJ的模板,别人写的模板比较可靠也方便自己学习理解,然后一些概念的则是学习了一些论文,下面的内容可以看作对别人模板的理解心得,以及对论文的收获体会. LCT支持的主要是一种树路径上的操作,譬如说对u和v之间的路径上询问点权的和,询问点权的最大值,对所有点权加一个数,置为一个树等等.它和树链剖分不同的是,它支持将这个树上的边切掉,也支持将两个树…

Query on The Trees Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 4002    Accepted Submission(s): 1749 Problem Description We have met so many problems on the tree, so today we will have a que…

LCT: 分割.合并子树,路径上全部点的点权添加一个值,查询路径上点权的最大值 Query on The Trees Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others) Total Submission(s): 2582    Accepted Submission(s): 1208 Problem Description We have met so many problems…

Problem Description We have met so many problems on the tree, so today we will have a query problem on a set of trees. There are N nodes, each node will have a unique weight Wi. We will have four kinds of operations on it and you should solve them ef…

http://acm.hdu.edu.cn/showproblem.php?pid=4010 (题目链接) 题意 link cut tree板子 Solution link cut tree 细节 注意第二个询问切的是什么 代码 // hdu4010 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #includ…

Problem Description We have met so many problems on the tree, so today we will have a query problem on a set of trees. There are N nodes, each node will have a unique weight Wi. We will have four kinds of operations on it and you should solve them ef…

Problem Description We have met so many problems on the tree, so today we will have a query problem on a set of trees. There are N nodes, each node will have a unique weight Wi. We will have four kinds of operations on it and you should solve them ef…

题意: 给出一颗树,有4种操作: 1.如果x和y不在同一棵树上则在xy连边 2.如果x和y在同一棵树上并且x!=y则把x换为树根并把y和y的父亲分离 3.如果x和y在同一棵树上则x到y的路径上所有的点权值+w 4.如果x和y在同一棵树上则输出x到y路径上的最大值 动态树入门题: #include <iostream> #include <cstdio> using namespace std; const int MAXN = 333333; struct node { int v…