POI2012 ODL-Distance】的更多相关文章

2790: [Poi2012]Distance Time Limit: 40 Sec  Memory Limit: 128 MBSubmit: 225  Solved: 115[Submit][Status][Discuss] Description 对于两个正整数a.b,这样定义函数d(a,b):每次操作可以选择一个质数p,将a变成a*p或a/p, 如果选择变成a/p就要保证p是a的约数,d(a,b)表示将a变成b所需的最少操作次数.例如d(69,42)=3. 现在给出n个正整数A1,A2,.…
[BZOJ2790][Poi2012]Distance Description 对于两个正整数a.b,这样定义函数d(a,b):每次操作可以选择一个质数p,将a变成a*p或a/p, 如果选择变成a/p就要保证p是a的约数,d(a,b)表示将a变成b所需的最少操作次数.例如d(69,42)=3. 现在给出n个正整数A1,A2,...,An,对于每个i (1<=i<=n),求最小的j(1<=j<=n)使得i≠j且d(Ai,Aj)最小. Input 第一行一个正整数n (2<=n&…
POI2012题解 这次的完整的\(17\)道题哟. [BZOJ2788][Poi2012]Festival 很显然可以差分约束建图.这里问的是变量最多有多少种不同的取值. 我们知道,在同一个强连通分量中的变量的相对大小是限制死了的,即这个强连通分量中的最大值减去最小值不为\(\inf\),而这个区间中的所有数一定都可以被取到(因为这里的边权只有\(0,\pm1\)嘛),所以一个强连通分量对答案的贡献是这个强连通分量中的最长路\(+1\).对于不在同一个强连通分量中的变量,其相对大小不受限制,取…
P3533 [POI2012]RAN-Rendezvous 题目描述 Byteasar is a ranger who works in the Arrow Cave - a famous rendezvous destination among lovers. The cave consists of nn chambers connected with one-way corridors. In each chamber exactly one outgoing corridor is ma…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…
Given a non-empty string str and an integer k, rearrange the string such that the same characters are at least distance k from each other. All input strings are given in lowercase letters. If it is not possible to rearrange the string, return an empt…
You want to build a house on an empty land which reaches all buildings in the shortest amount of distance. You can only move up, down, left and right. You are given a 2D grid of values 0, 1 or 2, where: Each 0 marks an empty land which you can pass b…
This is a follow up of Shortest Word Distance. The only difference is now word1 could be the same as word2. Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. word1 and word2 may be…
This is a follow up of Shortest Word Distance. The only difference is now you are given the list of words and your method will be called repeatedly many times with different parameters. How would you optimize it? Design a class which receives a list…