Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1. The Maximum Subsequence is the continuous subsequence which has the largest sum of its elements. For exampl…
1007 Maximum Subsequence Sum (25分) Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1≤i≤j≤K. The Maximum Subsequence is the continuous subsequence which has…
1007 Maximum Subsequence Sum (25 分) Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1. The Maximum Subsequence is the continuous subsequence which has the l…
题目 1007 Maximum Subsequence Sum (25分) Given a sequence of K integers { N1, N2, ..., N**K }. A continuous subsequence is defined to be { N**i, N**i+1, ..., N**j } where 1≤i≤j≤K. The Maximum Subsequence is the continuous subsequence which has the large…
1007 Maximum Subsequence Sum (25)(25 分) Given a sequence of K integers { N~1~, N~2~, ..., N~K~ }. A continuous subsequence is defined to be { N~i~, N~i+1~, ..., N~j~ } where 1 <= i <= j <= K. The Maximum Subsequence is the continuous subsequence…
1007. Maximum Subsequence Sum (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj} where 1 <= i <= j <= K. The …
题目 Given a sequence of K integers { N1 , N2 , ..., NK }. A continuous subsequence is defined to be { Ni , Ni+1 , ..., Nj } where 1≤i≤j≤K. The Maximum Subsequence is the continuous subsequence which has the largest sum of its elements…
Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, Ni+1, ..., Nj } where 1. The Maximum Subsequence is the continuous subsequence which has the largest sum of its elements. For exampl…
题意: 给出一个整数K(K<=10000),输入K个整数.输出最大区间和,空格,区间起点的数值,空格,区间终点的数值.如果有相同的最大区间和,输出靠前的.如果K个数全部为负,最大区间和输出0,区间起点的数值为a[1],区间终点的数值为a[n]. AAAAAccepted code: #include<bits/stdc++.h> using namespace std; ]; int main(){ int n; cin>>n; int mx=-1e9,ans=-1e9; ,…
