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leetcode -- 二进制 在学习编程语言的运算符时,大部分语言都会有与,或等二进制运算符,我在初期学习这些运算符的时候,并没有重点留意这些运算符,并且在后续的业务代码中也没有频繁的使用过,直到后来的一些算法题目和源码中经常遇到它们的身影,这些二进制运算符相比普通的运算符具有更快的效率,比如hashMap的源码就是将%替换成了&.我们在日常的很多需求都是可以转化为二进制运算符来完成的,这篇文章整理我在刷leetcode的时候遇到的一些二进制题目,对于很多问题,其实我们是没有意识来用这些二进制…
338. Counting Bits(计算小于n的各个数值对应的二进制1的个数) 思路:通过奇偶判断,if i是偶数,a[i]=a[i/2],if i是奇数,a[i]=a[i-1]+1. class Solution { public: vector<int> countBits(int num) { vector<, ); ;i<=num;i++) { ) res[i] = res[i-]+;//如果尾数为1,那么结果就是奇数,等于前一个值加1 else res[i] = res…
class Solution: def addBinary(self, a, b): """ :type a: str :type b: str :rtype: str """ a, b = int(a, 2), int(b, 2) return bin(a + b)[2:] i = Solution() print(i.addBinary('1010', '1011'))…
Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written in bin…
Special binary strings are binary strings with the following two properties: The number of 0's is equal to the number of 1's. Every prefix of the binary string has at least as many 1's as 0's. Given a special string S, a move consists of choosing two…
Give a string s, count the number of non-empty (contiguous) substrings that have the same number of 0's and 1's, and all the 0's and all the 1's in these substrings are grouped consecutively. Substrings that occur multiple times are counted the numbe…
Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0. Example 1: Input: 22 Output: 2 Explanation: 22 in binary is 0b10110. In the…
二进制手表顶部有 4 个 LED 代表小时(0-11),底部的 6 个 LED 代表分钟(0-59). 每个 LED 代表一个 0 或 1,最低位在右侧. 例如,上面的二进制手表读取 “3:25”. 给定一个非负整数 n 代表当前 LED 亮着的数量,返回所有可能的时间. 案例: 输入: n = 1 返回: ["1:00", "2:00", "4:00", "8:00", "0:01", "0:0…
LeetCode:二进制手表[401] 题目描述 二进制手表顶部有 4 个 LED 代表小时(0-11),底部的 6 个 LED 代表分钟(0-59). 每个 LED 代表一个 0 或 1,最低位在右侧. 例如,上面的二进制手表读取 “3:25”. 给定一个非负整数 n 代表当前 LED 亮着的数量,返回所有可能的时间. 案例: 输入: n = 1 返回: ["1:00", "2:00", "4:00", "8:00", &q…
LeetCode:二进制求和[67] 题目描述 给定两个二进制字符串,返回他们的和(用二进制表示). 输入为非空字符串且只包含数字 1 和 0. 示例 1: 输入: a = "11", b = "1" 输出: "100" 示例 2: 输入: a = "1010", b = "1011" 输出: "10101" 题目分析 分三部分分别运算.考虑进位值: Java题解 class Solut…