People were running up to us, and screaming and hitting us, and throwing stones and eggs. "They were kicking us, spitting at us, swearing at us.Reenex 好唔好" His captors claimed they were marching him through parts of the city that had been bombed…

看代码: #include <stdio.h> #include <fcntl.h> int key1(){ asm("mov r3, pc\n"); } int key2(){ asm( "push {r6}\n" "add r6, pc, $1\n" "bx r6\n" ".code 16\n" "mov r3, pc\n" "add r3, $0x…

How To Handle MLOG$_AP_SUPPLIER_SITES_AL, MLOG$_AP_SUPPLIERS Growing So Much? Having Lots of Data (文档 ID 2108515.1) 转到底部 In this Document Goal   Solution   References APPLIES TO: Oracle Payables - Version 12.0.0 and laterInformation in this document…

[CF471E]MUH and Lots and Lots of Segments 题意:给你平面上n条水平或竖直的,端点在整点处的线段.你需要去掉一些线段的一些部分,使得剩下的图形:1.连通,2.无环,3.端点依旧位于整点处. $n\le 2\times 10^5$ 题解:如果把整点看成点的话,那么这题让你求的就是一棵生成树.一棵生成树的边数就是这个连通块内点数-1,所以我们找到最大的连通块将其点数-1就是答案. 具体实现中,我们先进行扫描线,用并查集维护连通性,用线段树快速查找区间中点的数量…

I have to say besides computer science study, I'm also interested in Leg mechanism. Share two keywords: Leg mechanism and the strandbeest mechanism There is an interesting github project doing the simulaion and you can play with it.    https://github…

P1715 [USACO16DEC]Lots of Triangles好多三角形 题目描述 农民约翰希望通过卖出他拥有的一部分土地来增加收入.他在这片土地上种了\(N\)棵树(\(3\le N\le 300\)),每棵树都可以用一个二维网格图上的一个坐标来表示,没有三棵树是共线的.约翰想以3棵树做顶点围成三角形来分割地,以确定地的大小和形状,基于约翰所有树可能组成的三树组合,当然有\(L=\binom{N}{3}\)种可能考虑分割贩卖的土地切块. 一块分出的三角形土地有价值\(v\),\(v\)…

How To Determine The Cause Of Lots Of Redo Generation Using LogMiner (Doc ID 300395.1) APPLIES TO: Oracle Database - Enterprise Edition - Version 8.1.7.4 to 10.2.0.5 [Release 8.1.7 to 10.2]Oracle Database - Enterprise Edition - Version 11.2.0.1 and l…

pwnable从入门到放弃第八题. Download : http://pwnable.kr/bin/leg.cDownload : http://pwnable.kr/bin/leg.asm ssh leg@pwnable.kr -p2222 (pw:guest) 先下载这两个文件:leg.c #include <stdio.h> #include <fcntl.h> int key1(){ asm("mov r3, pc\n"); } int key2(){…

查看原题代码: #include <stdio.h> #include <fcntl.h> int key1(){ asm("mov r3, pc\n"); } int key2(){ asm( "push {r6}\n" "add r6, pc, $1\n" "bx r6\n" ".code 16\n" "mov r3, pc\n" "add r3,…

In ES6, IIFE is not necessary: // IIFE写法 (function () { var tmp = ...; ... }()); // 块级作用域写法 { let tmp = ...; ... } 另外,ES6也规定,函数本身的作用域,在其所在的块级作用域之内. function f() { console.log('I am outside!'); } (function () { if(false) { // 重复声明一次函数f function f() {…