POJ3279 Catch That Cow（BFS）

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POJ3279 Catch That Cow（BFS）

本文来源于:http://blog.csdn.net/svitter 意甲冠军:给你一个数字n, 一个数字k.分别代表主人的位置和奶牛的位置,主任能够移动的方案有x+1, x-1, 2*x.求主人找到奶牛的时间(奶牛不移动) 题解:最基础的BFS可是脑子犯抽WA了3遍- = 注意: 1.数组范围1~1<<5 2.visit去重.(BFS最基础的) 代码: #include <iostream> #include <stdio.h> #include <string…

HDU 2717 Catch That Cow （bfs）

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2717 Catch That Cow Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12615 Accepted Submission(s): 3902 Problem Description Farmer John has been…

POJ 3278 Catch That Cow（bfs）

传送门 Catch That Cow Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 80273 Accepted: 25290 Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 10…

HDU 2717 Catch That Cow（BFS）

Catch That Cow Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer…

Catch That Cow（BFS）

Catch That Cow Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10166 Accepted Submission(s): 3179 Problem Description Farmer John has been informed of the location of a fugitive cow and wants…

***参考Catch That Cow（BFS）

Catch That Cow Time Limit : 4000/2000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 67 Accepted Submission(s) : 22 Problem Description Farmer John has been informed of the location of a fugitive cow and wants to c…

Catch That Cow （bfs）

Catch That Cow bfs代码 #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<string> #include<vector> #include<stack> #include<bitset> #include<cstdlib> #include<cmath>…

poj 3278（hdu 2717） Catch That Cow（bfs）

Catch That Cow Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9753 Accepted Submission(s): 3054 Problem Description Farmer John has been informed of the location of a fugitive cow and wants…

题解报告：hdu 2717 Catch That Cow（bfs）

Problem Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. F…

poj 3278 Catch That Cow （bfs）

题目:http://poj.org/problem?id=3278 题意: 给定两个整数n和k 通过 n+1或n-1 或n*2 这3种操作,使得n==k 输出最少的操作次数 #include<stdio.h> #include<string.h> #include<queue> using namespace std; ]; struct node { int x,step; }; int bfs(int n,int k) { if(n==k) ; queue<n…

hdu 2717:Catch That Cow（bfs广搜，经典题，一维数组搜索）

Catch That Cow Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6383 Accepted Submission(s): 2034 Problem Description Farmer John has been informed of the location of a fugitive cow and wants…

【OpenJ_Bailian - 4001】 Catch That Cow（bfs+优先队列）

Catch That Cow Descriptions: Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same numbe…

HDU 2717 Catch That Cow(常规bfs）

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=2717 Catch That Cow Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 20259 Accepted Submission(s): 5926 Problem Description Farmer John has been i…

Catch That Cow（BFS广搜）

Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer Jo…

hdu 2717 Catch That Cow（BFS，剪枝）

题目 #include<stdio.h> #include<string.h> #include<queue> #include<algorithm> using namespace std; struct tt { int step,tem; }; ]; queue <tt> q; int bfs(tt s,tt e) { tt front,temp; q.push(s); visit[s.tem]=; while(!q.empty()) {…

POJ 3278 Catch That Cow（BFS 剪枝）

题目链接:http://poj.org/problem?id=3278 这几次都是每天的第一道题都挺顺利,然后第二道题一卡一天. = =,今天的这道题7点40就出来了,不知道第二道题在下午7点能不能出来.0 0 先说说这道题目,大意是有个农夫要抓牛,已知牛的坐标,和农夫位置. 并且农夫有三种移动方式,X + 1,X - 1,X * 2.问最少几步抓到牛. 開始觉得非常easy的,三方向的BFS就能顺利解决.然后在忘开标记的情况下直接广搜,果然TLE,在你计算出最少位置之前.牛早跑了. 然后反应过…

POJ——3278 Catch That Cow（BFS队列）

相比于POJ2251的三维BFS,这道题做法思路完全相同且过程更加简单,也不需要用结构体,check只要判断vis和左右边界的越界情况就OK. 记得清空队列,其他没什么好说的. #include<iostream> #include<queue> #include<cstring> #include<cstdio> using namespace std; const int maxn=100001; bool vis[maxn]; int step[max…

Catch That Cow （BFS)

题目: Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer John has t…

Catch That Cow（bfs)

Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer Jo…