Three companies decided to order a billboard with pictures of their logos. A billboard is a big square board. A logo of each company is a rectangle of a non-zero area. Advertisers will put up the ad only if it is possible to place all three logos on…

Three companies decided to order a billboard with pictures of their logos. A billboard is a big square board. A logo of each company is a rectangle of a non-zero area. Advertisers will put up the ad only if it is possible to place all three logos on…

D. Three Logos Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/581/problem/D Description Three companies decided to order a billboard with pictures of their logos. A billboard is a big square board. A logo of each company is…

Corporate Identity Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3308    Accepted Submission(s): 1228 Problem Description Beside other services, ACM helps companies to clearly state their “cor…

http://acm.hdu.edu.cn/showproblem.php?pid=2328 Corporate Identity Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 698    Accepted Submission(s): 281 Problem Description Beside other services, AC…

在ng2的开发过程中,Angular团队为我们带来了一个新的库 – zone.js.zone.js的设计灵感来源于Dart语言,它描述JavaScript执行过程的上下文,可以在异步任务之间进行持久性传递,它类似于Java中的TLS(thread-local storage: 线程本地存储)技术,zone.js则是将TLS引入到JavaScript语言中的实现框架. 那么zone.js能为我们解决什么问题呢?在回答这个问题之前,博主更希望回顾下在JavaScript开发中,我们究竟遇见了什么难题…

Description Input 第一行包含一个正整数testcase,表示当前测试数据的测试点编号.保证1≤testcase≤20. 第二行包含三个整数N,M,T,分别表示节点数.初始边数.操作数.第三行包含N个非负整数表示 N个节点上的权值.  接下来 M行,每行包含两个整数x和 y,表示初始的时候,点x和点y 之间有一条无向边, 接下来 T行,每行描述一个操作,格式为“Q x y k”或者“L x y ”,其含义见题目描述部分. Output 对于每一个第一类操作,输出一个非负整数表示答…

传送门 Fxx and string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 1007    Accepted Submission(s): 422 Description Problem DescriptionYoung theoretical computer scientist Fxx get a string which…

湘潭邀请赛的一题,名字叫"超级FFT"最终暴力就行,还是思维不够灵活,要吸取教训. 由于每组数据总量只有1e5这个级别,和不超过1e6,故先预处理再暴力即可. #include<cstdio> #include<iostream> #include<cstdlib> #include<cstring> #include<string> #include<algorithm> #include<map>…

这里是自定义了一个方法来获取viewpager private static ViewPager viewPager; public static ViewPager getMyViewPager(){ return viewPager; } 然后再你的点击事件中加入代码 public void onClick(View v) { S_MainActivity.getMyViewPager().setCurrentItem(1); } 简单又暴力…