POJ.3624 Charm Bracelet(DP 01背包) 题意分析 裸01背包 代码总览 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 13000 #define nnmax 3500 using namespace std; int dp[nmax]; int w[nnmax],d[nnmax]; int main…
题目链接:http://poj.org/problem?id=3624 Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list…
Charm Bracelet Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://poj.org/problem?id=3624 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (…
Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 38909   Accepted: 16862 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…
Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 34532   Accepted: 15301 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…
Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 45191   Accepted: 19318 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…
题目链接 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 52318   Accepted: 21912 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N(1…
Charm Bracelet Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 29295   Accepted: 13143 Description Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible fro…
题目链接:poj 3624 这是最基础的背包问题,特点是:每种物品仅有一件,可以选择放或不放.             用子问题定义状态:即F [i, v]表示前i件物品恰放入一个容量为v 的背包可以             获得的最大价值.则其状态转移方程便是:             F [i, v] = max{F [i − 1, v], F [i − 1, v − Ci ] + Wi }             这个方程非常重要,基本上所有跟背包相关的问题的方程都是由它衍生       …
DP 一直是心中痛,不多说了,这个暑假就坑在这上了. 这暑假第一道DP题,01背包问题. 题意是说物品有 重量和价值 ,但你能承受的重量有限,问你能带的最大价值. 这题数组开大点,尽管不知道有啥坑点,可是我数组开得大,直接1A了. 想想自己DP都是大问题,还要给学弟讲(tiao)题(jiao),真是忧伤. 仅仅能这几天通宵点出 DP 天赋.顺便贴上自己的理解,反正我也准备这样给学弟讲,假设有误,请路过大神指正. 论01背包的自我修养:         N个物品,M容量的包,最大价值为W.   …