链接 枚举两点(端点),循环遍历与直线相交的线段. #include <iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<stdlib.h> #include<vector> #include<cmath> #include<queue> #include<set> using namespace st…

称号: You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 145 Accepted Submission(s): 100   Problem Description Many geometry(几何)problems were designed in the ACM/IC…

Segments Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7739   Accepted: 2316 Description Given n segments in the two dimensional space, write a program, which determines if there exists a line such that after projecting these segments…

POJ 3304 Segments 大意:给你一些线段,找出一条直线可以穿过全部的线段,相交包含端点. 思路:遍历全部的端点,取两个点形成直线,推断直线是否与全部线段相交,假设存在这种直线,输出Yes.可是注意去重. struct Point { double x, y; } P[210]; struct Line { Point a, b; } L[110]; double xmult(Point p1, Point p2, Point p) { return (p1.x-p.x)*(p2.y…

Treasure Hunt Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4797   Accepted: 1998 Description Archeologists from the Antiquities and Curios Museum (ACM) have flown to Egypt to examine the great pyramid of Key-Ops. Using state-of-the-ar…

<题目链接> 题目大意: 给出一些线段,判断是存在直线,使得该直线能够经过所有的线段.. 解题思路: 如果有存在这样的直线,过投影相交区域作直线的垂线,该垂线必定与每条线段相交,问题转化为问是否存在一条线和所有线段相交. 如果存在这么一条直线,那么该直线一定能够移成经过两个端点的形式.枚举所有线段的两个端点,判断该直线和所有线段是否相交即可. #include <iostream> #include <math.h> #include <cstdio> us…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1558 题意是在坐标系中,当输入P(注意是大写,我当开始就wa成了小写)的时候输入一条线段的起点坐标和终点坐标,当输入Q的时候输入n,然后输出与第n条线段相交的线段有多少条 首先判断线段是否相交,在算法导论p577上有介绍 线段A(x1,y1)-B(x2,y2),所在直线L1方程为F1(x,y)=0;线段C(x3,y3)-D(x4,y4),所在直线L2方程为F2(x,y)=0; 如何判断两条线段有交点:(…

链接: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=1010 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=29328#problem/B Area Time Limit: 2 Seconds       Memory Limit: 65536 KB       Special Judge Jerry, a middle school student, ad…

题意:给出n条线段,问你是否存在一条直线让他与所有线段相交. 思路:枚举两条直线的起点和终点做一条直线,看他是否与所有线段相交. #include<cstdio> #include<cmath> #include<iostream> #include<algorithm> #include<vector> #include<stack> #include<cstring> #include<queue> #in…

Segments Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8579   Accepted: 2608 Description Given n segments in the two dimensional space, write a program, which determines if there exists a line such that after projecting these segments…