Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string s, sort it in decreasing order based on the frequency of the characters. The frequency of a character is the number of times it appears in the string. Return the sorted string. If there are multiple answers, return any of them. 考察了map的…
[抄题]: Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and '…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
题目: Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'…
https://leetcode.com/problems/sort-characters-by-frequency/ Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 优先级队列 排序 日期 题目地址:https://leetcode.com/problems/sort-characters-by-frequency/description/ 题目描述 Given a string, sort it in decreasing order based on the frequency of character…
给定一个字符串,请将字符串里的字符按照出现的频率降序排列.示例 1:输入:"tree"输出:"eert"解释:'e'出现两次,'r'和't'都只出现一次.因此'e'必须出现在'r'和't'之前.此外,"eetr"也是一个有效的答案. 示例 2:输入:"cccaaa"输出:"cccaaa"解释:'c'和'a'都出现三次.此外,"aaaccc"也是有效的答案.注意"cacaca&q…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…
Wiggle Sort: 注意:解法一是每次i增加2,题目不是保证3个3个的情况,而是整个数组都要满足要求. 解法一错误版本: 如果nums的长度是4,这种情况下nums[i+1]会越界.但是如果你用的是i和i-1的组合,一定可以不会越界,因为i不越界i-1就一定不会越界,for循环控制i,i越界了整个循环就结束了. class Solution { public: void wiggleSort(vector<int>& nums) { sort(nums.begin(),nums.…
跳跃空间(链表)排序 选择排序(selection sort),插入排序(insertion sort) 选择排序(selection sort) 算法原理:有一筐苹果,先挑出最大的一个放在最后,然后再跳出一个筐里剩下的最大的一个,放在刚才跳出来的最大的前面,以此类推,最后就排好顺序了. 代码: //从起始于位置p的n个元素中选出最大者,所以n>1 template<typename T> ListNode<T>* List<T>::selectMax(ListN…
连续线性空间排序 起泡排序(bubble sort),归并排序(merge sort) 1,起泡排序(bubble sort),大致有三种算法 基本版,全扫描. 提前终止版,如果发现前区里没有发生交换,就说明前区已经有序了,直接终止了.但是有个效率低下的地方,就是右边界hi是每次循环向前移动一个单元 跳跃版,在提前终止版的基础上,解决右边界hi移动效率低下的问题.解决思路:每次循环后,记录下最后一次的交换位置A,然后让hi=交换位置A,所以hi就可以跳跃移动多个单元了. 基本版代码实现 //冒泡…
http://www.practice.geeksforgeeks.org/problem-page.php?pid=493 Sorting Elements of an Array by Frequency Given an array of integers, sort the array according to frequency of elements. For example, if the input array is {2, 3, 2, 4, 5, 12, 2, 3, 3, 3,…
http://www.geeksforgeeks.org/sort-elements-by-frequency-set-2/ #include <iostream> #include <vector> #include <algorithm> #include <queue> #include <stack> #include <string> #include <fstream> #include <map>…
1.参数解释 -t 设置分隔符 -k 设置比较域(列) -n 按数字比较 -g 科学记数法方式比较 -o 设置输出文件,与“>”相比可以设置输出到原文件,“>”会清空原文件 -r 降序(大->小)排列 -u 删除相同行 2.实例演示 文件内容 [@ibi-genome temp]$ cat temp : : : 使用-k -t指定列()及分隔符(:) [@ibi-genome temp]$ sort -k2 -t':' temp : : : :4 使用-n指定以数字形式排序 &当…
使用归并排序对链表进行排序 O(nlgn) 的时间效率 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* sortList(ListNode* head) { if (head == NULL ||…
基数排序称为卡片分类,这是一个比较早的时间越多,排名方法. 现代计算机出现之前,它已被用于排序老式打孔卡. 说下基数排序的思想.前面我有写一个桶式排序,基数排序的思想是桶式排序的推广. 桶式排序:http://blog.csdn.net/alps1992/article/details/38132593 基数排序的思想是在于仅仅有10个桶.而不是最大数是多少就有多少个桶.假如我们有10个乱序的数字. 第一趟排序之后 0 1 512 343 64 125 216 27 8 729 0 1 2 3…
Java中常用的数组或集合排序的方法有两个,一个是java.util.Arrays中的静态方法Arrays.sort(),还有一个是java.util.Collections中的静态方法的Collections.sort()方法,下面分别介绍两种用法. 一.java.util.Arrays中的静态方法Arrays.sort() Arrays中的sort()方法主要是针对各种数据类型(基本数据类型和引用对象类型)的数组元素排序. ....... 关于引用对象类型数组的排序sort()方法要用到接口…
一.上代码 #include<bits/stdc++.h> using namespace std; #define MAXN 50000000 struct TS { int a, b, c; }; inline bool cmp(const TS& t1, const TS& t2) { if(t1.a != t2.a)return t1.a < t2.a; if(t1.b != t1.b)return t1.b < t2.b; return t1.c <…
题目大意:一串数字,使用如下方式排序: 先找到最小的数的位置$P_1$,将区间$[1,P_1]$反转,再找到第二小的数的位置$P_2$,将区间$[2,P_2]$反转,知道排序完成.输出每次操作的$P_i$,要求稳定排序(在括号外的是多组数据,括号内的是单组数据,四倍经验) 题解:可以用平衡数维护序列,只要维护求一个数的位置和区间翻转即可 卡点:查询位置时未$pushdown$ C++ Code: #include <cstdio> #include <algorithm> #def…
1.Comparable接口 这个接口顾名思义就是用于排序的,如果要对某些对象进行排序,那么该对象所在的类必须实现 Comparabld接口.Comparable接口只有一个方法CompareTo(),这个方法可以看做是指定的排序规则. 内置类已经实现了CompareTo方法,例如long 小于返回-1,等于返回0,大于返回1. 这里只举一个例子,例如int,double,Date等可以排序的内置类都已经实现了CompareTo方法,即指定了排序规则. 2.Collections.sort()和…
冒泡排序的过程是首先将第一个记录的关键字和第二个记录的关键字进行比较,若为逆序,则将两个记录交换,然后比较第二个记录和第三个记录的关键字.以此类推,直至第n-1个记录和第n个记录的关键字进行过比较为止.上述过程称为第一趟冒泡排序,接着第二趟对前面n-1个关键字进行同样操作,…… 快速排序是对冒泡排序的一种改进,通过一趟排序将记录分割成独立的两部分,其中一部分记录的关键字均比另一部分关键字小,可分别对这两部分记录以递归的方法继续进行排序,以达到整个序列有序. 单趟Partition()函数过程请看…
463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…