hdu 5475(打破固定思维OR线段树)】的更多相关文章

An easy problem Time Limit: 8000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1327    Accepted Submission(s): 624 Problem Description One day, a useless calculator was being built by Kuros. Let's assume that…
Dylans loves tree Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1444    Accepted Submission(s): 329 Problem Description Dylans is given a tree with N nodes. All nodes have a value A[i].Nodes…
Multiply game Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3224    Accepted Submission(s): 1173 Problem Description Tired of playing computer games, alpc23 is planning to play a game on numbe…
HDU 1394 Minimum Inversion Number(线段树求最小逆序数对) ACM 题目地址:HDU 1394 Minimum Inversion Number 题意:  给一个序列由[1,N]构成.能够通过旋转把第一个移动到最后一个.  问旋转后最小的逆序数对. 分析:  注意,序列是由[1,N]构成的,我们模拟下旋转,总的逆序数对会有规律的变化.  求出初始的逆序数对再循环一遍即可了. 至于求逆序数对,我曾经用归并排序解过这道题:点这里.  只是因为数据范围是5000.所以全…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1166 题目大意:给出n个点,每个点有一个值,现在有三种操作, 1.在i点加上j 2.在i点减去j 3.查询i,j区间总和 这其实是一道非常裸的线段树,但是我还是卡了好久,结果最后发现竟然是自己的freopen和代码习惯惹的祸.这道题我用了两种方法,一种是比较常规的版本,一种是不用结构体的静态树 首先来看一个常规的代码(带结构体) #include<cstdio> #include<cstri…
Color the ball Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7941    Accepted Submission(s): 4070 Problem Description N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球…
Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17737    Accepted Submission(s): 10763 Problem Description The inversion number of a given number sequence a1, a2, ...,…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5029 Problem Description The soil is cracking up because of the drought and the rabbit kingdom is facing a serious famine. The RRC(Rabbit Red Cross) organizes the distribution of relief grain in the disa…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1255 Description 给定平面上若干矩形,求出被这些矩形覆盖过至少两次的区域的面积.   Input 输入数据的第一行是一个正整数T(1<=T<=100),代表测试数据的数量.每个测试数据的第一行是一个正整数N(1<=N<=1000),代表矩形的数量,然后是N行数据,每一行包含四个浮点数,代表平面上的一个矩形的左上角坐标和右下角坐标,矩形的上下边和X轴平行,左右边和Y轴平行.坐…
做这道题之前,建议先做POJ 1151  Atlantis,经典的扫描线求矩阵的面积并 参考连接: http://www.cnblogs.com/scau20110726/archive/2013/04/13/3018702.html 线段树辅助——扫描线法计算矩形周长并(轮廓线):http://www.cnblogs.com/scau20110726/archive/2013/04/13/3018687.htmlhttp://blog.csdn.net/ophunter/article/det…