题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=3371 思路: 这道题很明显是一道最小生成树的题目,有点意思的是,它事先已经让几个点联通了.正是因为它先联通了几个点,所以为了判断连通性 很容易想到用并查集+kruskal. 不过要注意 这题有一个坑点,就是边数很多 上限是25000,排序的话可能就超时了.而点数则比较少 上限是500,所以很多人选择用Prim做.但我个人觉得这样连通性不好判断.其实边数多没关系,我们只要去重就好啦,用邻接矩阵存下两点…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=3371 Connect the Cities Description In 2100, since the sea level rise, most of the cities disappear. Though some survived cities are still connected with others, but most of them become disconnected. The…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3371 Problem Description In 2100, since the sea level rise, most of the cities disappear. Though some survived cities are still connected with others, but most of them become disconnected. The governmen…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=3371 984ms风险飘过~~~ /************************************************************************/ /* hdu Connect the Cities 最小生成树 题目大意:最小生成树,题目很长,题意很简单就是最小生成树.关键是构建图 */ /****************************************…

Connections between cities Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4057    Accepted Submission(s): 1178 Problem Description After World War X, a lot of cities have been seriously damage…

解题报告:有n个点,然后有m条可以添加的边,然后有一个k输入,表示一开始已经有k个集合的点,每个集合的点表示现在已经是连通的了. 还是用并查集加克鲁斯卡尔.只是在输入已经连通的集合的时候,通过并查集将该集合的点标记到一起,然后剩下的就可以当成是普通的最小生成树来做了题目代码如下: #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<cstd…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=3371 题目不难 稍微注意一下 要把已经建好的城市之间的花费定义为0,在用普通Prim算法就可以了:我没有用克鲁斯卡尔算法(Kruskal's algorithm),因为这题数据比较大,而且要处理大量的数据使它为0,怕超时T^T..... #include<iostream> #include<cstdio> #include<algorithm> using namespa…

地址:http://acm.hdu.edu.cn/showproblem.php?pid=3371 其实就是最小生成树,但是这其中有值得注意的地方:就是重边.题目没有告诉你两个城市之间只有一条路可走,所以两个城市之间可能有多条路可以走. 举例: 输入可以包含 1 2 3  // 1到2的成本为3   1 2 5  //1到2的成本为5      因此此时应选成本较低的路. 然后,已经连通的城市之间的连通成本为0. 这题用G++提交得到984ms的反馈,用C++提交则得到484ms的反馈. 很想知…

Connect the Cities Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 9985    Accepted Submission(s): 2843 Problem Description In 2100, since the sea level rise, most of the cities disappear. Thou…

Problem Description Five hundred years later, the number of dragon balls will increase unexpectedly, so it's too difficult for Monkey King(WuKong) to gather all of the dragon balls together. His country has N cities and there are exactly N dragon bal…