[LeetCode] Number of 1 Bits 位1的个数】的更多相关文章

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…
描述 Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). 输入是一个无符号整数,返回其二进制表达式中数字位数为 ‘1’ 的个数. 解析 消除最后的1 观察一下 n 与 n-1 这两个数的二进制表示:对于 n-1 这个数的二进制来说,相对于 n 的二进制,它的最末位的一个 1 会变成 0,最末位一个 1…
编写一个函数,输入是一个无符号整数,返回的是它所有 位1 的个数(也被称为汉明重量).例如,32位整数 '11' 的二进制表示为 00000000000000000000000000001011,所以函数返回3. 详见:https://leetcode.com/problems/number-of-1-bits/description/ Java实现: public class Solution { // you need to treat n as an unsigned value publ…
题意: 提供一个无符号32位整型uint32_t变量n,返回其二进制形式的1的个数. 思路: 考察二进制的特性,设有k个1,则复杂度为O(k).考虑将当前的数n和n-1做按位与,就会将n的最后一个1去掉,重复这样的操作就可以统计出1的个数了.(2015年春季 小米实习生的笔试题之一) class Solution { public: int hammingWeight(uint32_t n) { ; while(n) { n&=n-; cnt++; } return cnt; } }; AC代码…
leetcode:Number of 1 Bits 代码均测试通过! 1.Number of 1 Bits 本题收获: 1.Hamming weight:即二进制中1的个数 2.n &= (n-1)[n = n & (n-1)]的用处 题目: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).…
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…
原题链接在这里:https://leetcode.com/problems/number-of-1-bits/ 题目: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 0…
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…
Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n. For example: Given n = 13, Return 6, because digit 1 occurred in the following numbers: 1, 10, 11, 12, 13. Hint: Beware of overflow.…