Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&qu…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 这个题目只要注意各种情况你就成功了一大半,特别要注意的是对进位赋值后可能产生的变化,以及最后一位进位为1时, 我们要把这个1插进来.同时注意字符串的低位是我们数值的高位 class Solution { public: string…
题目描述: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 解题思路: 使用StringBuilder,且使用进位. 代码如下: public class Solution { public String addBinary(String a, String b) { String…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 简单的二进制高精度加法. class Solution { public: string addBinary(string a, string b) { string ans=""; ,i=a.length()-,…
翻译 给定两个二进制字符串,返回它们的和(也是二进制字符串). 比如, a = "11" b = "1" 返回 "100". 原文 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 分析 我一開始写了这个算法,尽管实现…
Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 思路:二进制加法,比較简单.代码例如以下: public class Solution { public String addBinary(String a, String b) { int len = Math.max(a.l…
