PAT T1016 Uniqueness of MST】的更多相关文章

dfs判断连通块的数量,prim算法建立最小生成树并判断是否唯一~ #include<bits/stdc++.h> using namespace std; ; const int inf=1e9; int g[maxn][maxn]; int d[maxn]; int visit[maxn]; int N,M; struct edge { int v1,v2; }; vector<edge> vi; void dfs (int s) { visit[s]=true; ;i<…
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, namely, T for the top level, A for advance and B for basic; the 2nd - 4th digits are the test site number, ranged from 101 to 999; the 5th - 10th digits…
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, namely, T for the top level, A for advance and B for basic; the 2nd - 4th digits are the test site number, ranged from 101 to 999; the 5th - 10th digits…
Source: PAT A1153 Decode Registration Card of PAT (25 分) Description: A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, namely, T for the top level, A for advance and B for basic; the 2nd - 4th digits ar…
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, namely, T for the top level, A for advance and B for basic; the 2nd - 4th digits are the test site number, ranged from 101 to 999; the 5th - 10th digits…
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, namely, T for the top level, A for advance and B for basic; the 2nd - 4th digits are the test site number, ranged from 101 to 999; the 5th - 10th digits…
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, namely, T for the top level, A for advance and B for basic; the 2nd - 4th digits are the test site number, ranged from 101 to 999; the 5th - 10th digits…
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, namely, T for the top level, A for advance and B for basic; the 2nd - 4th digits are the test site number, ranged from 101 to 999; the 5th - 10th digits…
博客出处:http://blog.csdn.net/zhoufenqin/article/details/50497791 题目出处:https://www.patest.cn/contests/pat-a-practise 1001 题意:给出a+b,计算c=a+b,将c输出时每三个数加一个“,” 思路:数据范围比较小,根据特殊的数据范围,也可特殊求解,不解释 #include<iostream> #include<cstdio> #include<cstring>…
原题连接:https://pta.patest.cn/pta/test/16/exam/4/question/677 题目如下: The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each…