要是没有next_permutation这个函数,这些题觉得还不算特别水,不过也不一定,那样可能就会有相应的模板了.反正正是因为next_permutation这个函数,这些题包括之前的POJ1226,都变得简单起来. 排列 Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 17486   Accepted: 6970 Description 题目描述:  大家知道,给出正整数n,则1到n这n个数可以构成n!种排列,把这些排…

要是没有next_permutation这个函数,这些题认为还不算特别水,只是也不一定,那样可能就会有对应的模板了. 反正正是由于next_permutation这个函数.这些题包含之前的POJ1226,都变得简单起来. 排列 Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 17486   Accepted: 6970 Description 题目描写叙述:  大家知道,给出正整数n,则1到n这n个数能够构成n.种排列,把…

POJ2718 Smallest Difference Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6509   Accepted: 1773 Description Given a number of distinct decimal digits, you can form one integer by choosing a non-empty subset of these digits and writing…

题目链接: https://vjudge.net/problem/POJ-3187 题目大意: 输入n,sum,求1~n的数,如何排列之后,相邻两列相加,直到得出最后的结果等于sum,输出1~n的排列(杨辉三角)  3 1 2 4 //1~n 全排列中的一个排列  4 3 6  7 9 sum = 16 思路: 直接枚举1-n的全排列,判断之和是不是sum #include<iostream> #include<vector> #include<queue> #incl…

题目地址 简要题意: 输入两个数n和m,分别表示给你1--n这些整数,将他们按一定顺序摆成一行,按照杨辉三角的计算方式进行求和,求使他们求到最后时结果等于m的排列中字典序最小的一种. 思路分析: 不难推得第一行为n个数a1\a2\--\an时求得的和为i=0∑n-1 ai*(n-1Ci) 根据此公式,考虑到数据量比较小,只需要将原本按递增顺序依次排列好的1--n按next_permutation给出的递增全排列顺序逐个代入,如果结果与m相等就停止循环即可. 参考代码: #include<stdi…

http://poj.org/problem?id=3187 给定一个个数n和sum,让你求原始序列,如果有多个输出字典序最小的. 暴力枚举题,枚举生成的每一个全排列,符合即退出. dfs版: #include <iostream> #include <cstdio> #include <cmath> #include <vector> #include <cstring> #include <string> #include <…

                                                                                                            排列 Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 15934   Accepted: 6413 Description 题目描述: 大家知道,给出正整数n,则1到n这n个数可以构成n!种排列,把这些排列按照…

给出杨辉三角的顶点值,求底边各个数的值.直接DFS就好了 #include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<algorithm> #include<queue> #include<set> #include<map> #include<vector> #include<cmath&g…

一.题目 Description FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a certain order and then sum adjacent numbers to produce a new list with one fewer number. They repeat this until only a single n…

Backward Digit Sums Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4487   Accepted: 2575 Description FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a certain order and then sum ad…