//20142880 唐炳辉 石家庄铁道大学 #include<iostream> #include<string> using namespace std; #define Maxnum 32767 #define N 100 typedef struct { string Dianarr[N]; string info[N]; int arcs[N][N]; int DianNum,BianNum; }FloydStruct; int LocateVex(FloydStruct…

POJ 2240 Arbitrage / ZOJ 1092 Arbitrage / HDU 1217 Arbitrage / SPOJ Arbitrage(图论,环) Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For exa…

Arbitrage Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6360    Accepted Submission(s): 2939 Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform o…

Arbitrage http://acm.hdu.edu.cn/showproblem.php?pid=1217 Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1217 /************************************************************************/ /* hdu Arbitrage floyd求最短路径 题目大意:floyd算法,求得两点之间最短距离,(u,v) = min( (u,v),(u,w)+(w,v) ); 此题,是求其能够赚钱,即最大生成树,且过程是相乘的,公式:( u, v) =…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1217 题目大意:问你是否可以通过转换货币从中获利 如下面这组样例: USDollar 0.5 BritishPound BritishPound 10.0 FrenchFranc FrenchFranc 0.21 USDollar 可以通过US->Br->French->US这样转换,把1美元变成1*0.5*10*0.21=1.05美元赚取%5的利润. 解题思路:其实就相当于bellman-…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1217 题目大意:通过货币的转换,来判断是否获利,如果获利则输出Yes,否则输出No. 这里介绍一个STL中的map容器去处理数据,map<string,int>V,M; 现在我目前的理解是将字符串转换成数字,然后就是根据spfa的模板找最短路了..哇哈哈( ⊙o⊙ )哇 #include <iostream> #include <cstdio> #include <m…

Arbitrage Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British p…

Flody多源最短路 #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<map> #include<algorithm> #include<iostream> using namespace std; ; map<string,int>zh; string s,s1,s2; double jz[maxn][m…

给出一些国家之间的汇率,看看能否从中发现某些肮脏的......朋友交易. 这是Floyd的应用,dp思想,每次都选取最大值,最后看看自己跟自己的.....交易是否大于一.... #include<iostream> #include<cstring> #include<queue> #include<cstdio> #include<map> using namespace std; #define exp 0.00000001 map<s…